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Kamila [148]
4 years ago
5

(03.03 mc)when two mechanical waves have a displacement in the same direction, and they overlap, what will the resulting wave lo

ok like and why?
Physics
2 answers:
notka56 [123]4 years ago
6 0

Answer;

-The resulting wave would have a displacement equal to the sum of the two initial waves.

This property of a wave is called Constructive interference.

Explanation;

-When two mechanical waves have a displacement in the same direction, and they overlap, then the resulting wave would have a higher amplitude or displacement compared to the original waves. This is referred to as constructive interference.

-Constructive interference takes place when two mechanical waves that have positive displacements from the equilibrium position meet and coincide.

-On the other hand, destructive interference takes place when one mechanical wave has a positive displacement and the other a negative displacement meet and coincide.

notsponge [240]4 years ago
5 0
The waves would combine to form a wave with a displacement equal to the sum of the two initial waves. This is called constructive inteference.
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Consider a taut inextensible string. You shake the end of the string with some frequency, causing a wave to travel down the stri
masha68 [24]

Answer:

Part 1:

Option B is correct (It will remain unchanged).

Part 2:

Option C is correct (It will increase by a factor of √ 2)

Part 3:

Option E is correct (It will be half as fast/long.)

Part 4:

Option C is correct (It will increase by a factor of √ 2.)

Explanation:

Formula we are going to use:

V=f*λ

Where:

V is the speed of Sound

f is the frequency of wave

λ is the wavelength.

The speed of wave , tension and linear density have following relation:

V=\sqrt{F/\rho}

Where:

V is the speed of Sound (Initial)

F is the tension in string (Initial)

\rho is the linear density of string (Constant)

Terms:

V' is the new speed

f' is the new frequency

λ' is the wavelength

Solution:

Part 1:

From V=\sqrt{F/\rho}:

Speed of Sound is independent of the frequency of shaking so speed well remain unchanged.

Option B is correct (It will remain unchanged)

Part 2:

If F'=2F then

V=\sqrt{F/\rho}

V'=\sqrt{F'/\rho}\\V'=\sqrt{2F/\rho}\\V'=  \sqrt{2} * \sqrt{F/\rho}\\V'=\sqrt{2}V

Option C is correct (It will increase by a factor of √ 2)

Part 3:

Formula we are going to use:

V=f*λ

Given f'=2f,

Even though frequency is doubled we will keep velocities same. V=V' in order to find the changing wavelength.

V'=f'*λ'

f*λ=f'*λ'

f*λ=2f*λ'

Solving above Equation:

λ'=λ/2

Option E is correct (It will be half as fast/long.)

Part 4:

T'=2T means V'=\sqrt{2}V (From Part 1)

f'=f

Now:

V'=f'*λ'

\sqrt{2}f*\lambda=f'*\lambda '\\\sqrt{2}f*\lambda=f*\lambda '\\ \lambda '=\sqrt{2}*\lambda

Option C is correct (It will increase by a factor of √ 2.)

5 0
3 years ago
A coin is resting on the bottom of an empty container. The container is then filled to the brim three times, each time with a di
Virty [35]

Answer:

Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A

Explanation:

Let the depth of each section is h.

That means the real depth for each section is h.

Apparent depth is liquid A is 7 cm.

Apparent depth in liquid B is 6 cm.

Apparent depth in liquid C is 5 cm.

by the formula of the refractive index

n = real depth / apparent depth

where, n is the refractive index of the liquid.

For liquid A:

n_{A}=\frac{h}{7}    .... (1)

For liquid B:

n_{B}=\frac{h}{6}   ..... (2)

For liquid C:

n_{C}=\frac{h}{5}     ..... (3)

By comparing all the three equations

nc > nB > nA

Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A

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3 years ago
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lisabon 2012 [21]

Answer:

it should be -2m/s

Explanation:

Because it is going down from minutes 6-8. And down in most cases means negative. And since it is going down 2 it should be -2m/s.

Hope this helped!!

8 0
3 years ago
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Answer:

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