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Kamila [148]
3 years ago
5

(03.03 mc)when two mechanical waves have a displacement in the same direction, and they overlap, what will the resulting wave lo

ok like and why?
Physics
2 answers:
notka56 [123]3 years ago
6 0

Answer;

-The resulting wave would have a displacement equal to the sum of the two initial waves.

This property of a wave is called Constructive interference.

Explanation;

-When two mechanical waves have a displacement in the same direction, and they overlap, then the resulting wave would have a higher amplitude or displacement compared to the original waves. This is referred to as constructive interference.

-Constructive interference takes place when two mechanical waves that have positive displacements from the equilibrium position meet and coincide.

-On the other hand, destructive interference takes place when one mechanical wave has a positive displacement and the other a negative displacement meet and coincide.

notsponge [240]3 years ago
5 0
The waves would combine to form a wave with a displacement equal to the sum of the two initial waves. This is called constructive inteference.
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What net force acting on a 14 KG wagon produces an acceleration of 1.5 MS^2?
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21N

Explanation:

Given parameters:

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Force is a pull or push on a body that causes a body to change its state. It is expressed as:  

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Two bowling balls each have a mass of 6.8 kg. They are located next to each other with their centers 21.8 cm apart. What gravita
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6.49 x 10^-8 N

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Aligned magnetic domains are only present in which of the following?
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8 0
3 years ago
A 15 kg bucket of water is suspended by a very light ropewrapped around a solid uniform cylinder 0.300 m in diamter withmass 12.
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Answer:

Part a)

T = 42 N

Part b)

v_f = 11.8 m/s

Part c)

t = 1.7 s

Part d)

F = 159.7 N

Explanation:

Part a)

While bucket is falling downwards we have force equation of the bucket given as

mg - T = ma

for uniform cylinder we will have

TR = I\alpha

so we have

T = \frac{1}{2}MR^2(\frac{a}{R^2})

T = \frac{1}{2}Ma

now we have

mg = (\frac{M}{2} + m)a

a = \frac{mg}{(\frac{M}{2} + m)}

a = \frac{15 \times 9.81}{(6 + 15)}

a = 7 m/s^2

now we have

T = \frac{12 \times 7}{2}

T = 42 N

Part b)

speed of the bucket can be found using kinematics

so we have

v_f^2 - v_i^2 = 2 a d

v_f^2 - 0 = 2(7)(10)

v_f = 11.8 m/s

Part c)

now in order to find the time of fall we can use another equation

v_f - v_i = at

11.8 - 0 = 7 t

t = 1.7 s

Part d)

as we know that cylinder is at rest and not moving downwards

so here we can use force balance

F = T + Mg

F = 42 + (12 \times 9.81)

F = 159.7 N

5 0
3 years ago
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