A positive charge is moved from point A to point B along an equipotential surface. How much work is performed or required in mov
1 answer:
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Answer:
Magnitude of the force is 2601.9 N
Explanation:
m = 450 kg
coefficient of static friction μs = 0.73
coefficient of kinetic friction is μk = 0.59
The force required to start crate moving is .
but once crate starts moving the force of friction is reduced .
Hence to keep crate moving at constant velocity we have to reduce the force pushing crate ie .
Then the above pushing force will equal the frictional force due to kinetic friction and constant velocity is possible as forces are balanced.
Magnitude of the force
Answer:
Explanation:
Given:
- mass of vehicle,
- radius of curvature,
- coefficient of friction,
<u>During the turn to prevent the skidding of the vehicle its centripetal force must be equal to the opposite balancing frictional force:</u>
where:
coefficient of friction
normal reaction force due to weight of the car
velocity of the car
is the maximum velocity at which the vehicle can turn without skidding.
I really hope this helps
