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Hoochie [10]
3 years ago
15

What can electromagnetic waves travel through?

Physics
1 answer:
Kisachek [45]3 years ago
6 0
Electromagnetic waves do not require a medium to travel through. They can travel through empty space or matter.
You might be interested in
Which term names the part of a sound wave by which frequency or pitch is measured?
Oksanka [162]

Answer:

Hertz

Explanation:

How long is a sound wave? Sound frequency (pitch) is measured in Hertz. 1 Hz is one cycle per second.

7 0
1 year ago
Mt. Everest is 20,028 feet high. How many miles is this? ( there are 5,280 feet in a mile)
MAXImum [283]

20,028 feet is 3.793 miles

The summit of Mt. Everest is 29,029 ft above sea level. That's 5.498 miles.

6 0
3 years ago
Read 2 more answers
An electron is trapped in an infinite square-well potential of width 0.6 nm. If the electron is initially in the n = 4 state, wh
grandymaker [24]

Answer:

E₁ = 1.042 eV

E₄₋₃= 7.29 eV      

E₄₋₂= 12.50 eV

E₄₋₁= 15.63 eV

E₃₋₂= 5.21eV

E₃₋₁= 8.34eV

E₂₋₁= 3.13eV

Explanation:

The energy in an infinite square-well potential is giving by:  

E = \frac {h^{2} n^{2}}{8mL^{2}}      

<em>where, h: Planck constant = 6.62x10⁻³⁴J.s, n: is the energy state, m: mass of the electron and L: widht of the square-well potential </em>      

<u>The energy of the electron in the ground state, </u><u>n = 1</u><u>, is:  </u>

E_{1} = \frac {(6.62 \cdot 10^{-34})^{2} (1)^{2}}{(8) (9.11 \cdot 10^{-31}) (0.6 \cdot 10^{-9} m)^{2}}    

E_{1} = 1.67 \cdot 10^{-19} J = 1.042 eV      

The photon energies that are emitted as the electron jumps to the ground state is the difference between the states:                      

E_{\Delta n} = \Delta n^{2} E_{1}  

E_{(4 - 3)} = (4^{2} - 3^{2}) 1.042 eV = 7.29eV

E_{(4 - 2)} = (4^{2} - 2^{2}) 1.042 eV = 12.50eV

E_{(4 - 1)} = (4^{2} - 1^{2}) 1.042 eV = 15.63eV

E_{(3 - 2)} = (3^{2} - 2^{2}) 1.042 eV = 5.21eV

E_{(3 - 1)} = (3^{2} - 1^{2}) 1.042 eV = 8.34eV

E_{(2 - 1)} = (2^{2} - 1^{2}) 1.042 eV = 3.13eV    

Have a nice day!                          

7 0
2 years ago
A net force of 15 N is applied to a cart with a mass of 2.1 kg. What is the acceleration of the cart?
Shkiper50 [21]
Force = mass * acceleration
15 = 2.1 * a
a = 15/2.1 = 7.143 m/s^2
5 0
2 years ago
A positive charge Q is placed at the origin. Four other positive charges are placed on a circle in the x-y plane centered on Q a
Shkiper50 [21]
1. <span>FX = 0 since the bottom charges are symmetrical about the y axis and the top charge is aligned with the y-axis
3. </span><span>FY > 0 since the bottom charges do not equate the top charge. The bottom charges have horizontal components which is less than q and adding them all, will not result to 3q.</span>
5 0
3 years ago
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