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poizon [28]
3 years ago
7

Bumper car A (331 kg) moving east at 3.87 m/s hit stationary car B (208 kg). After, the car A moves .88 m/s east. What is the ve

locity of car B?
Physics
1 answer:
Gre4nikov [31]3 years ago
4 0

Answer:

Ub = 221.99m/s

Explanation:

(Ma x Ua)+(Mb x Ub) = (Ma + Mb)V

(331 x 3.87)+(208 x Ub) = (331 + 208)88

(1257.8) + (208 x Ub) = 47432

(208 x Ub) = 47432 - 1257.8

(208 x Ub) = 46174.2

Ub = 46174.2/208 = 221.99m/s

Ub = 221.99m/s

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Convert 66.2 mi/h to m/s. 1 mi = 1609 m.<br> Answer in units of m/s.
Kryger [21]

Answer:

Explanation:

66.2mi/h to m/s

\frac{1609m}{1mi}×\frac{66.2mi}{1h}×\frac{1h}{60min}×\frac{1min}{60s}

  1. mi will go with mi
  2. h with h
  3. min with min
  4. m/s is left

\frac{1609*66.2}{60*60}= 29.58772222

Pls make sure of the way of solving to be sure...

4 0
4 years ago
A musical chord consists of several notes, each formed by a sound wave of a different frequency. The three graphs show the patte
sweet [91]

Answer:

If a chord had notes with frequencies of 100, 1,000, and 6,000 Hz, the basilar membran would vibrate at multiple positions, with peaks at A, B, and C.

Explanation:

3 0
3 years ago
A wire 25 m long carries a current of 12 A from west to east. If the magnetic force on the wire due to Earth’s magnetic field is
ra1l [238]
<h2>Answer:</h2>

<em>1.33 x 10⁻ ⁴ T outwards.</em>

<em></em>

<h2>Explanation:</h2>

The equation for the magnetic force (F) on a wire whose length is L and carrying a current I in a magnetic field (B) that is uniform is given by;

F = ILB sin θ          ---------------------(i)

Where;

θ = angle between the direction of the current and that of the magnetic field.

From the question,

F = 4.0 × 10⁻² N

I = 12A

L = 25m

θ = 90°

<em>Substitute these values into equation(i) and solve as follows;</em>

4.0 × 10⁻² = 12 x 25 x B x sin 90°

4.0 × 10⁻² = 300 x B x 1

4.0 × 10⁻² = 300B

0.04 = 300B

B = \frac{0.04}{300}

B = 0.000133

B = 1.33 x 10⁻ ⁴ T

To get the direction of the magnetic field, the right-hand rule is used.

If the right hand fingers are positioned in the correct order specified by the right hand rule, then it would be seen that the magnetic field is directed outwards.

Therefore, the magnitude and direction of the magnetic field at this location is <em>1.33 x 10⁻ ⁴ T outwards.</em>

6 0
3 years ago
300 grams of ethanol is heated with 14640 Joules of energy to reach a final temperature of 30 °C. What was the initial temperatu
levacccp [35]

Answer:

10 °C

Explanation:

Applying

q = cm(t₂-t₁)............... Equation 2

Where q = heat energy, c = specific heat of ethanol, m = mass of ethanol, t₁ = initial temperature, t₂ = Final temperature.

Given: c = 2.44 J/g.°C,  m = 300 g, q = 14640 J, t₂ = 30°C

Substitute into equation 2 and solve for t₁

14640 = 2.44×300(30-t₁)

14640 = 732(30-t₁)

732(30-t₁) = 14640

(30-t₁)  = 14640/732

(30-t₁)  = 20

t₁ = 30-20

t₁ = 10 °C

6 0
3 years ago
Read 2 more answers
Sheryl always expects special treatment wherever she goes because, after all, she is better than everyone else. She could care l
Lelechka [254]

Explanation:

it attributes to Being pride of herself

6 0
3 years ago
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