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Arte-miy333 [17]
3 years ago
7

Number 14 please fast answer

Chemistry
2 answers:
frutty [35]3 years ago
8 0

Answer: A. Oxygen

Explanation:

Oxygen - 46.6%

Oxygen is the most abundant element in the Earth's crust. Oxygen makes up 467,100 ppm (parts per million) of the Earth's crust, or 46.6%. It exists as a major compound of the silicate minerals where it combines with other elements. It also exists as a compound in carbonates and phosphates. Oxygen has industrial, medical, and commercial purposes. It is used with acetylene to cut and weld metals. It is used in hospitals to ease respiratory disease and can also be used to manufacture explosives among other numerous uses.

Silicon - 27.7%

Silicon is the second most common element present in the crust with an abundance of 276,900 ppm. It exists as a compound in the mantle and the crust. In the crust, it exists combined with oxygen to form silicate minerals. It is found in the sand which is an abundant and easily accessible resource on Earth. Silicon is also recovered from quartzite, mica, and talc. From silicon, we get silicones used in hydraulic fluids, electric insulators, and lubricants among others. Solid silicon is majorly used as a semiconductor especially in computer hardware. It is used to make transistors in the electronic industry. Silicon is used in the aluminum industry in the making of aluminum alloys. It is used in the production of ceramics, glass, cosmetics, insecticides, some types of steel, and pharmaceutical products.

Aluminum - 8.1%

At 80,700 ppm, aluminum is the third most abundant element in Earth's crust. Aluminum does not exist as a lone element, and it is found as a compound. Abundant compounds of Aluminum include aluminum oxide, aluminum hydroxide, and potassium aluminum sulfate. Aluminum is extracted from its compounds largely through the Bayer and Hall-Heroult processes. The element ideal because of its light weight and Aluminum alloys are extensively used to make utensils foils, packaging materials. It is used in the manufacture of parts of automobiles, rockets, and machinery.

Iron - 5%

Iron exists in the earth’s crust, and its composition is 50,500 ppm. Iron extracted in the form of iron ores existing in iron oxide forms such as hematite and magnetite. Blast furnaces are used to recover iron from the iron ores. Iron has many extensive applications such as the making of steel. Iron is also used to make utensils and kitchen appliances. It is also used to make cast iron and wrought iron which is extensively utilized in many industries. Iron element will always react with water and oxygen and the surface of iron is ordinarily lustrous and silvery gray, but it has a tendency of oxidizing in the open air to produce hydrated iron oxide commonly known as rust. In its purest form iron is relatively soft and is hardened and strengthened in the smelting process by adding a small percentage of carbon. The addition of carbon of between 0.002% and 2.1% will result in steel that could be 1000 times harder compared to pure iron.

Hope this helps!!! Good luck!!! ;)

aleksley [76]3 years ago
5 0

Answer:

Go to google, I think you would find information about your question

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A Canadian dime weighs 1.75g and has a thickness of 1.22mm. A Canadian quarter weighs 4.4g and has a thickness of 1.58mm. You ha
balu736 [363]

The mass of the total number of coins is 1405 g.

Since the thickness of each dime is 1.22 mm and we have each pile being 61.0 mm tall, we need to determine the number of dimes in each pile by dividing the height of the pile by the thickness of each dime.

so, number of dimes in each pile = height of each pile/thickness of each dime = 61.0 mm/1.22 mm = 50 dimes.

Since we have 6 piles, the total number of dimes in all the piles is 6 piles × 50 dimes/pile = 300 dimes.

So, there are 300 dimes in the 6 piles.

Since each dime weighs 1.75 g, 300 dimes will weigh 1.75 g/dime × 300 dimes = 525 g.

In the pile of quarters, we have $ 50 worth of quarters.

Since each quarter = $ 0.25, the number of quarters in that pile is total worth of quarter/value of one quarter = $ 50/$ 0.25 = 200 quarters.

Since each quarter weighs 4.4 g, 200 quarters will weigh 4.4 g/quarter × 200 quarters = 880 g

So, the mass of the total number of coins = total mass of dimes + total mass of quarters = 525 g + 880 g = 1405 g

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What kind of change occurs when I’ve becomes liquid water
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Explanation:

Brainliest please

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What mass of TiCl4 must react with an excess of water to produce 50.0g of TiO2 if the reaction has a 78.9% yield
Kipish [7]

Answer:

\large \boxed{\text{150 g TiCl}_{4}}  

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:     189.68                  79.87

           TiCl₄ + 2H₂O ⟶ TiO₂ + 4HCl

m/g:                                 50.0

To solve this stoichiometry problem, you must

  • Convert the actual yield to the theoretical yield  
  • Use the molar mass of TiO₂ to convert the theoretical yield of TiO₂ to moles of TiO₂
  • Use the molar ratio to convert moles of TiO₂ to moles of TiCl₄
  • Use the molar mass of TiCl₄ to convert moles of TiCl₄ to mass of TiCt₄

1. Theoretical yield of TiO₂

\text{Theoretical yield} = \text{50.0 g actual} \times \dfrac{\text{100 g theoretical}}{\text{78.9 g actual}} = \text{63.37 g theoretical}

2.  Moles of TiO₂

\text{Mass of TiO}_{2} = \text{63.37 g TiO}_{2} \times \dfrac{\text{1 mol TiO}_{2}}{\text{79.87 g TiO}_{2} } = \text{0.7934 mol TiO}_{2}

3,  Moles of TiCl₄

The molar ratio is 1 mol TiO₂:1 mol TiCl₄.

\text{Moles of TiCl}_{4} = \text{0.7934 mol TiO}_{2} \times \dfrac{\text{1 mol TiCl}_{4}}{\text{1 mol TiO}_{2}} = \text{0.7934 mol TiCl}_{4}

4.  Mass of TiCl₄

\text{Mass of TiCl}_{4} = \text{0.7934 mol TiCl}_{4} \times \dfrac{\text{189.98 g TiCl}_{4}}{\text{1 mol TiCl}_{4}} =\textbf{150 g TiCl}_{\mathbf{4}} \\\\\text{You must use $\large \boxed{\textbf{150 g TiCl}_{\mathbf{4}}}$}

5 0
3 years ago
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