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Cerrena [4.2K]
3 years ago
6

Please help! The last answer I need!

Mathematics
1 answer:
ruslelena [56]3 years ago
6 0

Answer

I would choose the answer c

really hope that helps  

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I need an answer to this, I dont get it, wouldnt it be impossible due to like terms? g3b=5x+2
Serjik [45]

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Step-by-step explanation:

hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii bot

x^{2} x^{2} \geq x^{2} \neq \geq \geq

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2 years ago
2. Amanda is reading a 208 page novel for her English
Sloan [31]

Answer:

i think your question might be incomplete. the necessary part of the question seems to be missing.

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3 years ago
What is greater: 1) 0.48 or 6/15th? 2) 0.75 or 7/8th? 3) 7.025 or 7 1/8ths?
fgiga [73]
1) 0.48 3     2) 7/8     3) 7 1/8
4 0
3 years ago
You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu
aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to 180^{o}.

Let the exterior angle be represented by x^{o}, and the three interior angles of the triangle be represented by a^{o}, b^{o} and c^{o}.

Assume that the vertex angle c^{o} is the linear pair to the exterior angle x^{o}.

i.e            x^{o} + c^{o} = 180^{o}  (sum of angles on a straight line)

Thus,

i. a^{o} +  b^{o} = x^{o}  (sum of two opposite interior angles is equal to an exterior angle)

⇒ a^{o}  = x^{o} - b^{o}

Also,

b^{o}  = x^{o} - a^{o}

But,

a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

⇒ c^{o} = 180^{o} - (a^{o} +  b^{o})

and

a^{o} + b^{o} = 180^{o} - c^{o}

ii. a^{o} + b^{o} + c^{o} = 180^{o}   (sum of angles in a triangle)

a^{o} = 180^{o} - (b^{o} + c^{o})

Also,

a^{o} +  b^{o} = x^{o}

⇒ b^{o} = x^{o} - a^{o}

c^{o} = 180^{o} - x^{o}

8 0
3 years ago
Hello Help Plis…………..
Lostsunrise [7]

Answer:

7. 20 + 5 + 3/10 + 6/100

8. 7 + 4/10 + 2/100 + 5/1000

Step-by-step explanation:

We are writing two numbers in expanded form, to help, we can use the guide above both numbers. Expanded form is all about breaking apart a number by place value and putting them in an additional sequence.

Let's look at 7, 25.36.

There are the tens, ones, tenths, and hundredths place being used, therefore :

20 + 5 + 3/10 + 6/100

We can do the same for 8, 7.425.

There are ones, tenths, hundredths, and thousandths being used, therefore :

7 + 4/10 + 2/100 + 5/1000

8 0
2 years ago
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