Answer:
how do i use this site im new
Step-by-step explanation:
Use Law of Cooling:

T0 = initial temperature, TA = ambient or final temperature
First solve for k using given info, T(3) = 42

Substituting k back into cooling equation gives:

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:

Solve for x:

Sub back into original cooling equation, x = T(t)

Solve for t:

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM
Answer:
0.006 miles per hour
Step-by-step explanation:
We are given;
Speed in cm per minute ( 17 cm per min)
We are required to convert cm per minute to miles an hour
we need to know that;
1 miles = 160934 cm
1 hour = 60 minutes
We can convert 17 cm to miles and 1 minute to hours
17 cm = 17 ÷ 160934 cm
= 17/160934
1 minute = 1/60 hour
Therefore;
In miles per hour;
= (17/160934) ÷ (1/60)
= 0.00634 miles per hour
= 0.006 miles per hour
Therefore, 17 cm per minute is equivalent to 0.006 miles per hour
36 + 57 + 4 + 2 + 1 = 100 would do it.
The given equation is:
0 + 7y + 2 = 7y + 2
This equation is showing that addition of 0 leaves the expression unchanged. 0 is known as the Additive Identity this means if we add or subtract 0 from any expression, number or equation the result won't be changed.
Therefore, the equation satisfied the property of Additive Identity of Real Numbers.