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3 years ago

What’s the most distant object in the solar system

Physics

2 answers:

Scrat [10]3 years ago

7 0

Answer:

pluto

Explanation:

i had the same question

ki77a [65]3 years ago

7 0

Pluto Because it is the furthest away

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A 1.25-kg ball begins rolling from rest with constant angular acceleration down a hill. If it takes 3.60 s for it to make the fi

miv72 [106K]

Answer:

The time taken is $\Delta t = 1.5 \ s$

Explanation:

From the question we are told that

The mass of the ball is $m = 1.25 \ kg$

The time taken to make the first complete revolution is t= 3.60 s

The displacement of the first complete revolution is $\theta = 1 rev = 2 \pi \ radian$

Generally the displacement for one complete revolution is mathematically represented as

$\theta = w_i t + \frac{1}{2} * \alpha * t^2$

Now given that the stone started from rest $w_i = 0 \ rad / s$

$2 \pi =0 + 0.5* \alpha *(3.60)^2$

$\alpha = 0.9698 \ s$

Now the displacement for two complete revolution is

$\theta_2 = 2 * 2\pi$

$\theta_2 = 4\pi$

Generally the displacement for two complete revolution is mathematically represented as

$4 \pi = 0 + 0.5 * 0.9698 * t^2$

=> $t^2 = 25.9187$

=> $t= 5.1 \ s$

The time taken to complete the next oscillation is mathematically evaluated as

$\Delta t = t_2 - t$

substituting values

$\Delta t = 5.1 - 3.60$

$\Delta t = 1.5 \ s$

7 0

3 years ago

Every summer I drive to Pennsylvania. It is 895 km to get there. If I average 100 km/hr, how much time will I spend driving?

Ivan

Answer the time you bee spending driving iss 795 because 895-795=100

Explanation:

6 0

2 years ago

What would most likely cause the future acceleration of the expansion of the universe

irga5000 [103]

Answer:

never scared

that might help you

3 0

2 years ago

An airplane starts from rest at the end of a runway and accelerates at a constant rate. In the first second, the airplane travel

Licemer1 [7]

Answer:

$v=4.44\frac{m}{s}$

Explanation:

Given that the airplane starts from the rest (this is initial velocity equals to zero) and accelerates at a constant rate, position can be described like this: $x=v_{0}t +\frac{1}{2} at^{2}$ where x is the position, t is the time a is the acceleration and $v_{0}$ is initial velocity. In this way acceleration can be found. $a=\frac{2(x-v_{0}t) }{t^{2} } =\frac{2(1.11m-0)}{1s^{2} } =2.22\frac{m}{s^{2} }$ .

Now we are able to found velocity at any time with the formula: $v=v_{0} +at = 0\frac{m}{s} +(2.22\frac{m}{s^{2}}.2s)=4.44\frac{m}{s}$

3 0

3 years ago

The counter is 1.5 m high, and the bowl has a mass of 0.5 kg. How much gravitational energy is stored in the bowl-earth system?

alina1380 [7]

Answer:

7.35 J

Im assuming, upon answering the question, that the gravity in this scenario is 9.8? As 9.8 is the gravitational force upon the earth.

5 0

2 years ago