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QveST [7]
3 years ago
8

What is the relationship between the mass, velocity, and momentum of an object?

Physics
2 answers:
zloy xaker [14]3 years ago
7 0

Answer:

Explanation:

Momentum is the measurement of the motion of an object.

It is defined as the product of mass of object and velocity of the object.

Momentum = mass × velocity

It's SI unit is kgm /s.

It is a vector quantity.

den301095 [7]3 years ago
3 0
In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object. where m is the mass and v is the velocity. The equation<span> illustrates that momentum is directly </span>proportional<span> to an object's mass and directly </span>proportional<span> to the object's velocity.</span>
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Discuss how a photon (aka the light particle) can be affected by gravity despite being massless.
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Explanation:

Light is clearly affected by gravity, just think about a black hole, but light supposedly has no mass and gravity only affects objects with mass. On the other hand, if light does have mass then doesn't mass become infinitely larger the closer to the speed of light an object travels.

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2 years ago
How does a mirage occur in a deser?explain with a labelled diagram.​
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Answer:

Mirages happen when the ground is very hot and the air is cool.

Explanation:

They happen when light passes through two layers of air with different temperatures. The desert sun heats the sand, which in turn heats the air just above it. The hot air bends light rays and reflects the sky.

When you see it from a distance, the different air masses colliding with each other act as a mirror.

8 0
1 year ago
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A scientist is trying to predict the regions of the world most likely to see a decrease in natural resources from population cha
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<u><em>Developed countries will see a decrease in natural resources, because their population will decrease.</em></u>

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3 years ago
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PLEASE HELP ME PLEASE
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Answer:

For A

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5 0
2 years ago
In the physics lab, a block of mass M slides down a frictionless incline from a height of 35cm. At the bottom of the incline it
bogdanovich [222]

Solution :

Given :

M = 0.35 kg

$m=\frac{M}{2}=0.175 \ kg$

Total mechanical energy = constant

or $K.E._{top}+P.E._{top} = K.E._{bottom}+P.E._{bottom}$

But $K.E._{top} = 0$ and $P.E._{bottom} = 0$

Therefore, potential energy at the top = kinetic energy at the bottom

$\Rightarrow mgh = \frac{1}{2}mv^2$

$\Rightarrow v = \sqrt{2gh}$

      $=\sqrt{2 \times 9.8 \times 0.35}$      (h = 35 cm = 0.35 m)

      = 2.62 m/s

It is the velocity of M just before collision of 'm' at the bottom.

We know that in elastic collision velocity after collision is given by :

$v_1=\frac{m_1-m_2}{m_1+m_2}v_1+ \frac{2m_2v_2}{m_1+m_2}$

here, $m_1=M, m_2 = m, v_1 = 2.62 m/s, v_2 = 0$

∴ $v_1=\frac{0.35-0.175}{0.5250}+\frac{2 \times 0.175 \times 0}{0.525}

      $=\frac{0.175}{0.525}+0$

     = 0.33 m/s

Therefore, velocity after the collision of mass M = 0.33 m/s

 

3 0
2 years ago
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