Answer:
Janet jumps off a high diving platform with a horizontal velocity of 2.89 m per s and lands in the water 1.5 s later. How high is the platform?
Platform is 11.025 meters high .
Explanation:
we have Vx = 2.89 m/s
time taken = 1.5 seconds
height of the platform = ?
so,
As Janet is jumping from a high diving platform from a certain unknown height their must be involvement of gravity in action.
we can use,
h = Vi*t+(1/2)*g*t^2
where ,
h = height
Vi = initial horizontal velocity that will be zero
t = time in seconds
g = gravity due to acceleration
now put the values
h = 0+(1/2)*(9.8)*(1.5)^2
h = 11.025-m
<span>F= ma force is directed on the working surface so 40 = m x 2 hence
m must be 20 units needed are probably kg</span>
Answer:
v = 26. 88 m/s +23 m/s
Explanation:
u = 23 m/s, r = 150 cm, u₁ = 2.0 m/s, s =2.0 m
Solve s'
To determine the speed of the trick to the highway
Now to determine the velocity highway is going to be
v = ds/dt + u
v = 26. 88 m/s +23 m/s
Answer:
Bobby walked a total of 16 meters
Explanation:
10 + 6 = 16
If an atom gains electrons, it develops a negative charge equal to the number of electrons gained.
So the net charge on the copper atom which gained 2 electrons will be -2.
