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3 years ago

Can somebody please help me solve this algebra problem: 3p+2r=n solve for p

1 answer:

8 0

3p + 2r = n.....subtract 2r from both sides
3p = -2r + n...divide both sides by 3
p = (-2r + n)/3 or p = -2/3r + n/3 or p = -2/3r + 1/3n

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Barry is 8 years older than his sister. In 3 years, he will be twice as old as she will be then. How old is each now?

Colt1911 [192]

Answer:

Step-by-step explanation:

Present age of Barry = b

Present age of sister = s

Barry is 8 years older than his sister means if we subtract 8 from present age of Barry both will be of equal age

s=b-8 ............(1)

In 3 years means we have to add 3 in their present age

s+3=b+3

then

he will be twice as old as

2(s+3)=(b+3

2s+6=b+3

2s=b+3-6

2s=b-3...............(2)

Put the value of s from (1) to (2), we have

2(b-8)=b-3

2b-16=b-3

2b-b=-3+16

b=13

Put the value of b in (1)

s=13-8

s=5

Present age of Barry = b = 13

Present age of sister = s = 5

7 0

3 years ago

Write an equation of the parabola that opens up whose vertex (−1, 2) is 3 units from the focus. (Vertex form or Parabola Form is

TEA [102]

Answer:

y2 = 4ax (opens right, a > 0)

y2 = -4ax (opens right, a > 0)

x2 = 4ay (opens up, a > 0)

x2 = -4ay (opens down, a > 0)

Vertex at (h, k) :

(y - k)2 = 4a(x - h) (opens right, a > 0)

(y - k)2 = -4a(x - h) (opens right, a > 0)

(x - h)2 = 4a(y - k) (opens up, a > 0)

(x - h)2 = -4a(y - k) (opens down, a > 0)

Equation of a Parabola in Vertex form

Vertex at Origin :

y = ax2 (opens up, a > 0)

y = -ax2 (opens down, a > 0)

x = ay2 (opens right, a > 0)

x = -ay2 (opens left, a > 0)

Vertex at (h, k) :

y = a(x - h)2 + k (opens up, a > 0)

y = -a(x - h)2 + k (opens down, a > 0)

x = a(y - k)2 + h (opens right, a > 0)

y = -a(y - k)2 + h (opens left, a > 0)

Step-by-step explanation:

7 0

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geniusboy [140]

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6 0

3 years ago

Read 2 more answers

PLZ HELP QUICK-------------->

sveticcg [70]

<h2>>>> Answer <<<</h2>

Let's check which polynomial is divisible by ( x - 1 ) using hit , trial and error method .

A ( x ) = 3x³ + 2x² - x

The word " divisible " itself says that " it is a factor "

Using factor theorem ;

Let;

=> x - 1 = 0

=> x = 1

Substitute the value of x in p ( x )

p ( 1 ) =

3 ( 1 )³ + 2 ( 1 )² - 1

3 ( 1 ) + 2 ( 1 ) - 1

3 + 2 - 1

5 - 1

This implies ;

A ( x ) is not divisible by ( x - 1 )

Similarly,

B ( x ) = 5x³ - 4x² - x

B ( 1 ) =

5 ( 1 )³ - 4 ( 1 )² - 1

5 ( 1 ) - 4 ( 1 ) - 1

5 - 4 - 1

5 - 5

This implies ;

B ( x ) is divisible by ( x - 1 )

Similarly,

C ( x ) = 2x³ - 3x² + 2x - 1

C ( 1 ) =

2 ( 1 )³ - 3 ( 1 )² + 2 ( 1 ) - 1

2 ( 1 ) - 3 ( 1 ) + 2 - 1

2 - 3 + 2 - 1

4 - 4

This implies ;

C ( x ) is divisible by ( x - 1 )

Similarly,

D ( x ) = x³ + 2x² + 3x + 2

D ( 1 ) =

( 1 )³ + 2 ( 1 )² + 3 ( 1 ) + 2

1 + 2 + 3 + 2

This implies ;

D ( x ) is not divisible by ( x - 1 )

<h2>Therefore ; </h2>

<h3>B ( x ) & C ( x ) are divisible by ( x - 1 ) </h3>

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Answer:

0,7

Step-by-step explanation:

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3 years ago