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Debora [2.8K]
3 years ago
10

Prove or give a counterexample:

Mathematics
1 answer:
natima [27]3 years ago
6 0

Answer: Although A and AT have the same eigenvalues, they may actually have different eigenvectors for that particular eigenvalue. Therefore A and AT have at least one eigenvector that aren't in common.

Step-by-step explanation:

These two attachment explains the provings and counterexamples briefly and simply

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