3 years ago

Which of the following quantities represent mass?

Physics

1 answer:

lisabon 2012 [21]3 years ago

6 0

Answer:

Explanation:

a ) 12.0 lbs - mass

b ) .34 g - mass

c ) 120 kg - mass

As lbs , g and kg are units of mass , these things represent mass . lbs is FPS unit of mass and kg is SI unit . g is CGS unit of force .

d ) 1600 kN It represents force because kN or kilonewton is unit of force .

e ) it represents , length or distance because m or metre is unit of length .

f ) 411 cm It represents length or distance because cm is smaller unit of length

g ) 899 MN or million newton . Like d ) It also represents force . Million newton is higher unit of force .

You might be interested in

An earth scientist who studies hydrosphere

ipn [44]

Oceanographer? I think that is what it is.

5 0

3 years ago

A car with a momentum (impulse) of 20,000 kg m/s collides with a wall and comes to a rest in 0.1 seconds. How much

Pani-rosa [81]

Answer:

» Force is 200,000 Newtons

Explanation:

${ \tt{force = \frac{impulse}{time} }} \\ \\ { \tt{force = \frac{20000}{0.1} }} \\ \\ { \tt{force = 200000 \: newtons}}$

8 0

3 years ago

Read 2 more answers

Which of the following pieces of laboratory equipment is not directly used to make measurements

RoseWind [281]

I believe the answer is a test tube.

4 0

4 years ago

Read 2 more answers

A ball dropped from a window strikes the ground 2.76 seconds later. How high is the window above the ground

sweet [91]

Answer:

37.33m

Explanation:

Using the equation of motion

S = ut + 1/2gt^2

Time t = 2.76secs

g = 9.8m/s^2

S = 0 + 1/2(9.8)(2.76)^2

S = 4.9*7.6176

S = 37.33

Hence the window is 37.33m above the ground

7 0

3 years ago

A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i

levacccp [35]

Answer:

The minimum speed must the car must be 13.13 m/s.

Explanation:

The radius of the loop is 17.6 m. We need to find the minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top.

We know that, mg be the weight of car and rider, which is equal to the centripetal force.

$mg = \dfrac{mv^2}{r}\\v = \sqrt{rg}\\v = \sqrt{17.6\times 9.8}\\v = 13.13\ m/s\\$

So, the minimum speed must the car must be 13.13 m/s.

5 0

3 years ago