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irina [24]
4 years ago
11

An aircraft has a mass of 3.30 x 105 kg. At a certain instant during its landing, its speed is 45.2 m/s. If the braking force is

3.30 x 105 N, what is the speed of the airplane 12.1 s later?
Physics
1 answer:
melamori03 [73]4 years ago
8 0
Ultraconservative the future and I have been working with the following questions.
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If an athlete expends 3480. kJ/h, how long does she have to play to work off 1.00 lb of body fat? Note that the nutritional calo
Sunny_sXe [5.5K]

Answer:

The time required by the Athlete to work off 1.00 lb of body fat = 0.296 minute

Explanation:

1 lb of body fat = 4.1 k cal

1 k cal = 4.184 Kilo joule

1 lb of body fat = 4.1 × 4.184 = 17.1544 Kilo joule

Athlete expends 3480 Kilo joule in one hour

⇒ Time required to expand 3480 Kilo joule  = 60 minute

⇒ Time required to expand 1 Kilo joule = \frac{60}{3480} \frac{min}{KJ}

⇒ Time required to expand 17.1544 Kilo joule = \frac{60}{3480} × 17.1544 = 0.296 min

Therefore the time required by the Athlete to work off 1.00 lb of body fat = 0.296 minute

6 0
3 years ago
A snow ball is thrown upward at a speed of 27 m/s. How high is the snow ball 3.5 seconds later? Also, how fast is it moving at t
JulijaS [17]

Answer:

Dy = 111.66 [m]

t  = 3.5 [s]

Explanation:

To solve this problem we must use the equations of kinematics.

v_{f} = v_{o} - (g*t)\\

where:

Vf = final velocity [m/s]

Vo = initial velocity = 27 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time = 3.5 [s]

Note: The negative sign of the equation means that the gravity acceleration goes in opposite direction

Vf = 27 - (9,81*3,5)

Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)

To find how high the snowball was we must use the following equation:

Dy=v_{o} *t+\frac{1}{2}*g*t

Dy = (27*3.5) + (0.5*9.81*3.5)

Dy = 94.5 + (17.16)

Dy = 111.66 [m]

5 0
3 years ago
The total number of stars in the observable universe is roughly equivalent to:
musickatia [10]

Answer:

The number of grains of sand on all the beaches on Earth

Explanation:

if we assume grain of sand has an average size , then the number of grains of sand on all the beaches on Earth is roughly 7.5 \times 10^{18}

The total number of stars in the observable universe is roughly equivalent to 1 billion trillion. which is roughly  equal to the number of grains of sand on all the beaches on Earth.

3 0
3 years ago
Consider a machine of mass 70 kg mounted to ground through an isolation system of total stiffness 30,000 N>m, with a measured
kvv77 [185]

Answer:

a)0.0229 m

b)0.393 rad

c)1.57

d)707.6 N

e)0.298 m/s

Explanation:

Given:

  • Mass of the machine, m=70 kg
  • Stiffness of the system, k=30000 N/m
  • Damping ratio=0.2
  • Damping force, F=450 N
  • Angular velocity \omega=13\ \rm rad/s

a)We know that the amplitude X at steady state is given by

X=\dfrac{\dfrac{F_0}{m}}{\sqrt{\omega_n^2-\omega^2)^2 +(2\rho \omega_n\omega)^2}}\\

Where

  • \omega_n=\sqrt{\dfrac{k}{m}}\\\\=\sqrt{\dfrac{30000}{70}}\\\\=20.7\ \rm rad/s
  • \omega=13\ \rm rad/s
  • \rho=0.2
  • F_0=450\ \rm N
  • m=70\ \rm kg

X=\dfrac{\dfrac{450}{70}}{\sqrt{20.7^2-13^2)^2 +(2\times 0.2\times20.7\times13)^2}}\\[tex]X=0.0229\ \rm m

b) The phase shift of the motion is given by

\tan\phi=\dfrac{2\rho \omega_n \omega }{\omega_n^2-\omega^2}\\\\\dfrac{2\times0.2\times20.7\times13 }{20.7^2-\13^2}\\\\\phai=0.393\\

c)Transmissibility ratio is given by

T.R.=\sqrt{\dfrac{1+(2\rho r)^2}{(1-r^2)^2+{(2\rho r)^2}}}\\\\T.R.=\sqrt{\dfrac{1+(2\times0.2\times0.628)^2}{(1-0.628^2)^2+{(2\times0.2\times0/628)^2}}}\\\\=1.57

d)The magnitude of the force transmitted to the ground is

F_T=(T.R)\times F_0\\\\=450\times1.57\\\\=707.6\ \rm N

e)The maximum velocity is given by V_{max}

V_{max}=\omega A_0\\\\=13\times 0.0229\\\\=0.298\ \rm m/s

6 0
3 years ago
Ethnocentrism can lead to all the following except __________. A. tolerance B. stereotypes C. racism D. discrimination
lara [203]
A. Tolerance. When you have an "Us vs Them" mentality it can never lead to acceptance.
4 0
4 years ago
Read 2 more answers
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