All categories

2 years ago

Refer back to your data. List all indicators of chemical change that you observed.

2 answers:

3 0

Below are the 5 main indicators of chemical change.

Chemical change indicators:
Color change
Temperature change
Precipitate formation
Odor
Bubble formation

I hope this helps!

kiruha [24]2 years ago

3 0

Answer:

Some indicators of chemical change were

- gas formation

- turned into a new substance

- color changed

- temperature changed

- light and heat were formed

You might be interested in

Calculate the potential energy of a 5 kg object sitting at the top of a 2 meter ramp.

trapecia [35]

The formula used to find potential energy is P.E. = M * G * H (P.E. is potential energy, M is mass, G is gravitational pull, and H is height). So the answer to your question is 5 * 9.8 * 2, which equals 98.

5 0

2 years ago

The amount of time required for 2 successive wave crests to pass a fixed point is called wave ________.

mihalych1998 [28]

I believe this is known as wave period.
hope this helps!

7 0

2 years ago

A toroidal coil of N turns has a central radius b and a square cross section of side a. Find its self-inductance.

Xelga [282]

Answer:

$L = \frac{\mu_0 N^2 (a^2)}{2\pi b}$

Explanation:

As we know that magnetic field due to torroid is given as

$B = \frac{\mu_0 N i}{2\pi b}$

this is approximately constant magnetic field along the axis of the torroid

now the flux linked with one coil of the torroid is given as

$\phi = B.A$

$\phi = \frac{\mu_0 N i}{2\pi b}(a^2)$

now total flux of N number of coils is given as

$\phi_{total} = \frac{\mu_0 N^2 i(a^2)}{2\pi b}$

now we know that self inductance is the property of coil in which flux of the coil will link with the current in the coil

So we know that

$L = \frac{\phi}{i}$

$L = \frac{\mu_0 N^2 (a^2)}{2\pi b}$

3 0

2 years ago

A certain field line diagram illustrates the electric field due to three particles that carry charges 5.0 μC, -3.0 μC, and -2.0

4vir4ik [10]

Answer:

Explanation:

Number of lines emanate from + 5 micro coulomb is 15 .

They terminates at negative charges that means at - 3 micro coulomb and - 2 micro Coulomb.

the electric field lines terminates at - 3 micro Coulomb and - 2 micro Coulomb is in the ratio of 3 : 2.

So the lines terminating at - 3 micro coulomb

= $\frac{3}{5}\times 15 = 9$

So the lines terminating at - 2 micro coulomb

= $\frac{2}{5}\times 15 = 6$

So, the number of filed lines terminates at - 2 micro Coulomb are 6.

4 0

2 years ago

Calculate the speed of a car that traveled 200 kilometers in 3 hours.

nignag [31]

Answer:

The units (km/h) tell you how to do this! 200km/3h = 66.66666666…. BUT technically you only have ONE significant digit: 3 so 66.666… rounded to ONE digit is 70km/h but that is probably not important in this intro class so V = 66.67 or 67 km/h

8 0

2 years ago

Read 2 more answers