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Leviafan [203]
3 years ago
15

Interactions of current carrying wires

Physics
1 answer:
koban [17]3 years ago
7 0
Physics stack exchange
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I believe the answer would be C. point z

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The outer shell electrons in metals are not tightly bound to the nuclei of their atoms they are free to roam throughout the mate
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The pumps which supplies energy to move the water from the ground to a high elevation. The charges that flow throughout the wires.

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I WILL MARK BRAINLIEST!!ASAP!!! Wet Lab - Coulomb's Law lab from edge!!
snow_tiger [21]

Answer:

h

Explanation:

Coulomb's law, or Coulomb's inverse-square law, is an experimental law[1] of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force.[2] The law was first discovered in 1785 by French physicist Charles-Augustin de Coulomb, hence the name. Coulomb's law was essential to the development of the theory of electromagnetism, maybe even its starting point,[1] as it made it possible to discuss the quantity of electric charge in a meaningful way.[3]

The law states that the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them,[4]

{\displaystyle F=k_{\text{e}}{\frac {q_{1}q_{2}}{r^{2}}}}{\displaystyle F=k_{\text{e}}{\frac {q_{1}q_{2}}{r^{2}}}}

Here, ke is Coulomb's constant (ke ≈ 8.988×109 N⋅m2⋅C−2),[1] q1 and q2 are the signed magnitudes of the charges, and the scalar r is the distance between the charges.

The force is along the straight line joining the two charges. If the charges have the same sign, the electrostatic force between them is repulsive; if they have different signs, the force between them is attractive.

Being an inverse-square law, the law is analogous to Isaac Newton's inverse-square law of universal gravitation, but gravitational forces are always attractive, while electrostatic forces can be attractive or repulsive.[2] Coulomb's law can be used to derive Gauss's law, and vice versa. In the case of a single stationary point charge, the two laws are equivalent, expressing the same physical law in different ways.[5] The law has been tested extensively, and observations have upheld the law on the scale from 10−16 m to 108 m.[5]

7 0
3 years ago
Our favorite program runs in 10 seconds on computer A, which has a 4 GHz. clock. We are trying to help a computer designer build
Alona [7]

Answer:

The rate clock is about

F = 8 GHz

Explanation:

f₁ = 4 G Hz , t₁ = 10 s , t₂ = 6s , f₂ = 1.2 f₁

Can organize to find the rate clock the designer build to the target so

X / 4 Ghz = 10 s , 1.2 X /  Y = 6 s

X * Y = 10 s  ⇒ F = 10 s

1.2 * 4 G Hz = 6 s

F = 10 * ( 1.2 * 4 G Hz ) / 6

F = 10 * ( 1.2 * 4 x 10 ⁹ Hz )  /  6

F = 8 x 10 ⁹ Hz

F = 8 GHz

3 0
3 years ago
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