Answer:
24.47 L
Explanation:
Using the general gas law equation:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = 0.0821 Latm/molK
T = temperature (K)
According to the provided information in this question,
P = 1.0 atm
V = ?
n = 1 mol
T = 25°C = 25 + 273 = 298K
Using PV = nRT
V = nRT ÷ P
V = 1 × 0.0821 × 298 ÷ 1
V = 24.465 ÷ 1
V = 24.465
V = 24.47 L
It matters to the aerodynamics of it because sometimes it's good to have the weight but only if it can take it.
In scientific notation, a number is less than ten but more than one.
Move the decimal point from 0, 250.000 <- this is the same as 250 to between 2 and 5.
I had to move two spaces.
2.5^2
I hope this helps!
~kaikers
<u>Answer:</u> 2.00 atm
<u>Explanation:</u>
The gas is kept under the same temperature in this problem. Assuming the amount of gas is constant, we can apply the Boyle's law.
The Boyle's law equation,
P₁V₁ = P₂V ₂
Plug in the values,
1.00 atm x 4.0 L = P₂ x 2.0 L
Simplify,
4.00 atm L = 2 P₂ L
Now flip the equation,
2 P₂ L = 4.00 atm L
Dividing both sides by 2 we get,
P₂ = 2.00 atm
