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3 years ago

When an object falls to the ground, potential energy is most likely transformed into

Chemistry

1 answer:

pentagon [3]3 years ago

8 0

Answer:

kinetic energy

Explanation:

When the object is released, the gravitational potential energy is gradually converted into kinetic energy as it picks up speed.

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How many total oxygen (O) atoms are present in the products side of the equation C2H5OH + 3O2 → 2CO2 + 3H2O?

kifflom [539]

Answer:

There are seven oxygen atoms in total on the product side.

Explanation:

The oxygen atom is present in both the species of CO₂ and H₂O. As there are two molecules of CO₂, so the number of oxygen atoms from it will be 4. There are three molecules of H₂O in the product side so oxygen atoms from it will be three. So, the total number of oxygen from both species is seven.

3 0

4 years ago

how is the ammonium ion (NH4)1- and the oxalate ion (C2O4) 2- combine written in the ionic compound formed?

lana66690 [7]

Answer: Shown In Photo

Explanation:

just crisscross as shown in photo good luck i suck @ explaining

4 0

3 years ago

Use the word bank to complete the charts about the metrics system measurement

Aloiza [94]

Answer:

Length

- centimetre

- millimetre

- kilometre

- meter

Mass

- gram

- kilogram

Capacity

- liter

- millilitre

I don't know why mass is there but hope this helps! :)

5 0

3 years ago

Consider the reaction 4HCl(g) + O2(g)2H2O(g) + 2Cl2(g) Using standard thermodynamic data at 298K, calculate the entropy change f

Ulleksa [173]

<u>Answer:</u> The value of $\Delta S^o$ for the surrounding when given amount of HCl gas is reacted is 73.21 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$4HCl(g)+O_2(g)\rightarrow 2H_2O(g)+2Cl_2(g)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(Cl_2(g))})+(2\times \Delta S^o_{(H_2O(g))})]-[(4\times \Delta S^o_{(HCl(g))})+(1\times \Delta S^o_{(O_2(g))})]$

We are given:

$\Delta S^o_{(O_2(g))}=205.14J/K.mol\\\Delta So_{(HCl(g))}=186.91J/K.mol\\\Delta S^o_{(Cl_2(g))}=223.07J/K.mol\\\Delta S^o_{(H_2O(g))}=188.82J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (223.07))+(2\times (188.82))]-[(4\times (186.91))+(1\times (205.14))]\\\\\Delta S^o_{rxn}=-129J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-129) J/K = 129 J/K

We are given:

Moles of HCl gas reacted = 2.27 moles

By Stoichiometry of the reaction:

When 4 mole of HCl gas is reacted, the entropy change of the surrounding will be 129 J/K

So, when 2.27 moles of HCl gas is reacted, the entropy change of the surrounding will be = $\frac{129}{4}\times 2.27=73.21J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of HCl gas is reacted is 73.21 J/K

3 0

3 years ago

Which Sphere does condensation occur.

Xelga [282]

Answer:

The atmosphere, I believe.

Explanation:

4 0

3 years ago