Im bad at math can you help me

Mathematics

1 answer:

lidiya [134]3 years ago

6 0

Answer:

4to7

Step-by-step explanation:

i dont know

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I managed to prove JMK and KNJ to be congruent. How do I find that JLK is isoceles though. Please help.

Anni [7]

Answer:

Step-by-step explanation:

A triangle is isosceles if it has two equal sides and two equal angles.

From the diagram, the two perpendicular bisectors divides each base angle into 2 equal parts.

Since the 2 lines of the the perpendicular bisectors cuts across the midpoint of the triangle, it divides both lines JL and LK equally.

This means that lines JL and LK are equal.

Triangle JLK has 3 sides, JL, LK and JK.

Since lines JL and LK are equal, then

Triangle JLK is isosceles since it has two equal sides and 2 equal angles

5 0

4 years ago

From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th

wel

Answer:

$\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}$

Step-by-step explanation:

The width of a square is its side length.

The width of a circle is its diameter.

Therefore, the largest possible circle that can be cut out from a square is a circle whose diameter is equal in length to the side length of the square.

Formulas

$\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}$

$\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

$\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}$

If the diameter is equal to the side length of the square, then:
$\implies \sf r=\dfrac{1}{2}s$

Therefore:

$\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}$