The answer to 0 <span>≤ t/3 < 2 is
0 </span><span>≤ t < 6
The work:
You just have to multiply all the terms by 3 so you get rid of the 3 in the "t/3".
After multiplying you get the answer.
The graph: </span><span>
</span>
These two claims about markup and margin are <u>equivalent</u> because they discuss differently the same issue.
<h3>What are markup and margin?</h3>
A markup is a profit percent added to the cost price to determine the selling price. Thus, markup relates the percentage of profit to the cost price.
The profit margin relates the percentage of profit to the selling price.
<h3>Data and Calculations:</h3>
Selling price = 100%
Profit margin = 25%
Cost price = 75% (100% - 25%)
Markup = 33% (25%/75% x 100)
Thus, these two claims about markup and margin are <u>equivalent</u>.
Learn more about margin and markup at brainly.com/question/13248184
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Answer:
a) P(z<-0.66) = 0.2546
b) P(-1<z<1) = 0.6826
c) P(z>1.33) = 0.9082
Step-by-step explanation:
Mean = 300
Standard Deviation = 75
a) Less than 250 hours
P(X<250)=?
z = x - mean/ standard deviation
z = 250 - 300 / 75
z = -50/75
z = -0.66
P(X<250) = P(z<-0.66)
Looking for value of z = -0.66 from z score table
P(z<-0.66) = 0.2546
b. Between 225 and 375 hours
P(225<X<375)=?
z = x - mean/ standard deviation
z = 225-300/75
z = -75/75
z = -1
z = x - mean/ standard deviation
z = 375-300/75
z = 75/75
z = 1
P(225<X<375) = P(-1<z<1)
Looking for values from z score table
P(-1<z<1) = P(z<1) - P(z<-1)
P(-1<z<1) = 0.8413 - 0.1587
P(-1<z<1) = 0.6826
c. More than 400 hours
P(X>400) =?
z = x - mean/ standard deviation
z = 400-300/75
z = 100/75
z = 1.33
P(X>400) = P(z>1.33)
Looking for value of z = 1.33 from z-score table
P(z>1.33) = 0.9082
