I'll need a picture of your box plot to answer that question
Answer:
y=0.2x+29
Step-by-step explanation:
Given that:
y is the total monthly of the A Fee and Fee plan.
x is the number of monthly minutes used.
- If a customer uses 290 minutes, the monthly cost will be $87, we have the pair (290, 87)
- If the customer uses 980 minutes, the monthly cost will be $225, this is the coordinate pair (980, 225).
We want to obtain an equation in the form: y=mx+b
First, let us determine the slope, m
Given points (290, 87) and (980, 225):
<u>Slope</u>

Next, we determine the y-intercept, b.
Substituting the pair (290, 87) and m=0.2 in y=mx+b, we obtain
87=0.2(290)+b
b=87-0.2(290)=29
Therefore, our equation in the form y=mx+b is:
y=0.2x+29
Answer: 0.8238
Step-by-step explanation:
Given : Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with
and
.
Let x denotes the scores on a certain intelligence test for children between ages 13 and 15 years.
Then, the proportion of children aged 13 to 15 years old have scores on this test above 92 will be :-
![P(x>92)=1-P(x\leq92)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{92-106}{15})\\\\=1-P(z\leq })\\\\=1-P(z\leq-0.93)=1-(1-P(z\leq0.93))\ \ [\because\ P(Z\leq -z)=1-P(Z\leq z)]\\\\=P(z\leq0.93)=0.8238\ \ [\text{By using z-value table.}]](https://tex.z-dn.net/?f=P%28x%3E92%29%3D1-P%28x%5Cleq92%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B92-106%7D%7B15%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq%20%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq-0.93%29%3D1-%281-P%28z%5Cleq0.93%29%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%5Cleq%20-z%29%3D1-P%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3DP%28z%5Cleq0.93%29%3D0.8238%5C%20%5C%20%5B%5Ctext%7BBy%20using%20z-value%20table.%7D%5D)
Hence, the proportion of children aged 13 to 15 years old have scores on this test above 92 = 0.8238
Answer: 4 tomatoes
Step-by-step explanation:
Divide 3.36 by 0.84 = 4
yes it is right right right 100%