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shepuryov [24]
3 years ago
8

What is 100% of £70?

Mathematics
2 answers:
Margarita [4]3 years ago
5 0

Answer:70

Step-by-step explanation:

Julli [10]3 years ago
4 0

Answer: 70

Step-by-step explanation:

70/100 =

70%

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Which of the following interpretations for the given expression is correct? (29) the cube of the difference of the square of 5 t
masya89 [10]

Answer:

df

Step-by-step explanation:

fewf

5 0
2 years ago
A pack of 24 cans costs £6. Work out the cost of 5 cans.
VARVARA [1.3K]
<span>24 cans costs £6

6/24 = 0.25 each can

5 * 0.25 = </span><span>£1.25

answer: </span>£1.25 for <span>5 cans</span>
6 0
3 years ago
Read 2 more answers
PLEASE HELP!!! NEED HELP ASAP !!! WILL MARK BRAINLIEST !!!
Aleks04 [339]

Answer:

36 π square feet

Step-by-step explanation:

so the formula for area of a circle is  πr^2

so the radius is 6, which we can just plug in

π(6)^2

36π

so option 3

5 0
3 years ago
A small theater had 9 rows of 25 chairs each. An extra 7 chairs have just been brought in. How many chairs are in the
Alchen [17]

Answer:

232

Step-by-step explanation:

9 x 25 = 225   225 + 7 = 232

another way to find it

9 x 20 = 180   9 x 5 = 45   180 + 45 = 225 + 7 = 232

8 0
3 years ago
What is the sum of the first 51 consecutive odd positive integers?
Angelina_Jolie [31]
We call:

a_{n} as the set of <span>the first 51 consecutive odd positive integers, so:

</span>a_{n} = \{1, 3, 5, 7, 9...\}

Where:
a_{1} = 1
a_{2} = 3
a_{3} = 5
a_{4} = 7
a_{5} = 9
<span>and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

</span>a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}
<span>
Then:

</span>a_{n} = a_{1} + (n-1)d
<span>
So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

</span>S_{k} = ( \frac{a_{1} +  a_{k}}{2}  ).k
<span>
Therefore, we need to find:
</span>a_{k} =  a_{51}  

Given that a_{1} = 1, then:

a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1

Thus:
a_{k} = a_{51} = 2(51)-1 = 101

Lastly:

S_{51} = ( \frac{1 + 101}{2} ).51 = 2601 

4 0
3 years ago
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