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4 years ago

What can we say about the rock as it falls to Earth?

Physics

2 answers:

Mashutka [201]4 years ago

7 0

Answer:

The answer is A)

Explanation:

Nadya [2.5K]4 years ago

5 0

A) It accelerates as it falls.

Unless it is has no acceleration or deceleration then it will speed up because as its mass will weigh the rock down making it go faster.

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when electrical energy is used what type of energy is also produced and considered to be waste energy?

Dima020 [189]

Answer:

<em>Thermal energy</em>

Explanation:

<u>Electrical Energy </u>

The electrical energy has been found to be an excellent resource to power our modern lifestyle. It can be produced in several ways including hydroelectrical plants, thermal plants, nuclear plants, solar panels, among many others. Each one of them converts different types of energy into electrical energy.

When converting to electrical energy, some equipment is needed, like generators, transformers, cables, circuit breakers, and every kind of devices with specific functions to have a good and safe electrical service. Each device has an internal resistance that opposes the flow of current. The resistances produce thermal energy as a result of current flowing through them. It's not possible to avoid this waste of energy, electrical engineers do their best to use better materials and configurations to reduce the thermal waste to a minimum.

8 0

3 years ago

A string is wrapped several times around the rim of a small hoop with radius 8.00 cm and mass 0.180 kg. The free end of the stri

Dmitrij [34]

Answer:

(a). The angular speed of the rotating is 33.8 rad/s.

(b). The speed of its center is 2.7 m/s.

Explanation:

Given that,

Radius = 8.00 cm

Mass = 0.180 kg

Height = 75.0 m

We need to calculate the angular speed of the rotating

Using conservation of energy

$\dfrac{1}{2}I\omega_{1}^2+\dfrac{1}{2}mv_{1}^{2}+mgh_{1}=\dfrac{1}{2}I\omega_{2}^2+\dfrac{1}{2}mv_{2}^{2}+mgh_{2}$

Here, initial velocity and angular velocity are equal to zero.

$mgh_{1}=\dfrac{1}{2}I\omega_{2}^2+\dfrac{1}{2}mv_{2}^{2}+mgh_{2}$

$mg(h_{1}-h_{2})=\dfrac{1}{2}I\omega_{2}^2+\dfrac{1}{2}mv_{2}^{2}$

$mgH=\dfrac{1}{2}mr^2\omega_{2}^2+\dfrac{1}{2}m(r\omega_{2})^2$

Here, $H = h_{1}-h_{2}$

$gH=r^2\omega_{2}^2$

$\omega_{2}^2=\dfrac{gH}{r^2}$

$\omega_{2}=\sqrt{\dfrac{9.8\times75.0\times10^{-2}}{(8.00\times10^{-2})^2}}$

$\omega_{2}=33.8\ rad/s$

The angular speed of the rotating is 33.8 rad/s.

(b). We need to calculate the speed of its center

Using formula of speed

$v=r\omega$

Put the value into the formula

$v=8.00\times10^{-2}\times33.8$

$v=2.7\ m/s$

Hence, (a). The angular speed of the rotating is 33.8 rad/s.

(b). The speed of its center is 2.7 m/s.

3 0

3 years ago

Read 2 more answers

Calculate Neptune's mass given the acceleration due to gravity at the north pole is 11.529 m/s2 and the radius of Neptune at the

dolphi86 [110]

Answer:

The mass of Neptune is $1.023\times 10^{26}$ kilograms.

Explanation:

From Newton's Law of Gravitation, the gravitational acceleration of Neptune is determined by the following formula:

$g = \frac{G\cdot M}{R^{2}}$ (1)

Where:

$G$ - Gravitational constant, measured in cubic meters per kilogram-square second.

$M$ - Mass of the planet, measured in kilograms.

$R$ - Radius of the planet, measured in meters.

$g$ - Gravitational acceleration, measured in meters per square second.

If we know that $G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}$ , $g = 11.529\,\frac{m}{s^{2}}$ and $R = 24.340\times 10^{6}\,m$ , then the mass of Neptune is:

$M = \frac{g\cdot R^{2}}{G}$

$M = \frac{\left(11.529\,\frac{m}{s^{2}}\right)\cdot (24.340\times 10^{6}\,m)^{2} }{6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} }$

$M = 1.023\times 10^{26}\,kg$

The mass of Neptune is $1.023\times 10^{26}$ kilograms.

5 0

3 years ago

Science Seminar Question: Why did Vehicle 2 fall off the cliff in Claire's test of the collision scene but Vehicle 2 did not fal

asambeis [7]

Complete Question:

Check the file attached to get the complete question

Answer:

In the film Ice word Revenge, vehicle 2 did not fall of the cliff because, $Weight_{vehicle 1} < Weight_{vehicle 2}$ but in Claire's test, vehicle 2 off the cliff because $Weight_{vehicle 1} \geq Weight_{vehicle 2}$

Explanation:

In Claire's test, the weight of vehicle 1 is either equal to or greater than the weight of vehicle 2, so it was sufficient to push it down the cliff. In the film Ice word revenge, the weight of vehicle 1 is less than the weight of vehicle 2, it is not sufficient to make it fall off the cliff ( Note: Looking exactly the same in the movie, as Claire claimed, does not mean they have the same mass). Therefore if Claire wants a collision that will not make the vehicle 2 fall off the cliff, he should collide it with a vehicle of lesser mass/weight.

8 0

3 years ago

Resistance of a conductor is directly proportional to length. True or False

Yanka [14]

True.

As the length of the conductor increases, so also the resistance to the flow of current increases along the conductor.

7 0

3 years ago