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Sergeu [11.5K]
3 years ago
5

Calculate Neptune's mass given the acceleration due to gravity at the north pole is 11.529 m/s2 and the radius of Neptune at the

pole is 24,340 km.
Physics
1 answer:
dolphi86 [110]3 years ago
5 0

Answer:

The mass of Neptune is 1.023\times 10^{26} kilograms.

Explanation:

From Newton's Law of Gravitation, the gravitational acceleration of Neptune is determined by the following formula:

g = \frac{G\cdot M}{R^{2}} (1)

Where:

G - Gravitational constant, measured in cubic meters per kilogram-square second.

M - Mass of the planet, measured in kilograms.

R - Radius of the planet, measured in meters.

g - Gravitational acceleration, measured in meters per square second.

If we know that G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}, g = 11.529\,\frac{m}{s^{2}} and R = 24.340\times 10^{6}\,m, then the mass of Neptune is:

M = \frac{g\cdot R^{2}}{G}

M = \frac{\left(11.529\,\frac{m}{s^{2}}\right)\cdot (24.340\times 10^{6}\,m)^{2} }{6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} }

M = 1.023\times 10^{26}\,kg

The mass of Neptune is 1.023\times 10^{26} kilograms.

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Answer:

The velocity of the first block is 1.15m/s while of the second block 2.56m/s.

Explanation:

Momentum is only conserved in an isolated system, and because this problem requires us to find the value of the two variables, we need two equations; therefore, to conserved momentum the energy must be released in to the system only after the collision has occurred.

Therefore, from conservation of momentum

m_1v_1= m_1v_{1f}+m_2v_{2f}

0.4(2.4)= 0.4v_{1f}+0.5v_{2f}

\boxed{\:0.96= 0.4v_{1f}+0.5v_{2f}}

and from conservation of energy

$\frac{1}{2}m_1v_1^2+1.2 = \frac{1}{2} m_1v_{1f}^2+\frac{1}{2}m_2v_{2f}^2  $

m_1v_1^2+2.4 =  m_1v_{1f}^2+m_2v_{2f}^2}

$\boxed{\:3.804=  0.4v_{1f}^2+0.5v_{2f}^2.}$

Thus, we have two equations and two unknowns

(1). \: 0.4v_{1f}+0.5v_{2f}=0.96

{(2). \:  0.4v_{1f}^2+0.5v_{2f}^2 =3.804

which has solutions

(v_{1f}, v_{2f}) = (1.15,2.56)

and

(v_{1f}, v_{2f}) = (1.15,-2.56)

Since the blocks cannot pass through each other, the 0.5kg block cannot have v_{2f} = -2.56m/s  (moves to the left) while the 0.4 kg block has v_{1f} = 1.15m/s (moves to the right); therefore, we take the first solution for the velocities:

(v_{1f}, v_{2f}) = (1.15,2.56).

Thus , the velocity of the first block is 1.15m/s while of the second block 2.56m/s.

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3 years ago
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If the world population grows at a constant rate of 1.8% per annum, how many years will it take to double? A) 17.7 years
AleksandrR [38]

Answer:

after 38.8 years it will double

correct option is D 38.8 years

Explanation:

given data

population grows rate = 1.8%

to find out

how many years will it take to double

solution

we consider here initial population is x

so after 1 year population will be = (100% + 1.8% ) x = 1.018 x

and after n year population will be = 1.018^{n} x

so it will double

2x = 1.018^{n} x

take log both side

log 2 = n log (1.018)

n = \frac{log2}{log1.018}

n = 38.853

so after 38.8 years it will double

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4 0
3 years ago
A 1200-kg car is travelling east at a rate of 9 m/s. A 1600-kg truck is travelling south at a rate of 13 m/s. The truck accident
weeeeeb [17]

Answer:

Around 3.57m/s

Explanation:

p=mv

Let's denote the momentum, mass, and velocity of the car with the subscript 1, and for the truck use 2. After the collision, the combined momentum can be denoted with the subscript 3.

p_1=1200\cdot 9=10800 \\\\p_2=1600\cdot 13=20800 \\\\20800-10800=10000 \\\\1200kg+1600kg=2800kg \\\\10000=2800v_3 \\\\v_3\approx 3.57m/s

Hope this helps!

3 0
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Doss [256]

Answer:

The resultant velocity is <u>169.71 km/h at angle of 45° measured clockwise with the x-axis</u> or the east-west line.

Explanation:

Considering west direction along negative x-axis and north direction along  positive y-axis

Given:

The car travels at a speed of 120 km/h in the west direction.

The car then travels at the same speed in the north direction.

Now, considering the given directions, the velocities are given as:

Velocity in west direction is, \overrightarrow{v_1}=-120\ \vec{i}

Velocity in north direction is, \overrightarrow{v_2}=120\ \vec{j}

Now, since v_1\ and\ v_2 are perpendicular to each other, their resultant magnitude is given as:

|\overrightarrow{v_{res}}|=\sqrt{|\overrightarrow{v_1}|^2+|\overrightarrow{v_2}|^2}

Plug in the given values and solve for the magnitude of the resultant.This gives,

|\overrightarrow{v_{res}}|=\sqrt{(120)^2+(120)^2}\\\\|\overrightarrow{v_{res}}|=120\sqrt{2} = 169.71\ km/h

Let the angle made by the resultant be 'x' degree with the east-west line or the x-axis.

So, the direction is given as:

x=\tan^{-1}(\frac{|v_2|}{|v_1|})\\\\x=\tan^{-1}(\frac{120}{-120})=\tan^{-1}(-1)=-45\ deg(clockwise\ angle\ with\ the\ x-axis)

Therefore, the resultant velocity is 169.71 km/h at angle of 45° measured clockwise with the x-axis or the east-west line.

4 0
3 years ago
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