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vladimir2022 [97]
3 years ago
6

Which statement best describes the temperature dependence of an addition reaction? Addition reactions are thermodynamically impo

ssible. Addition reactions are thermodynamically disfavored at all temperatures. Addition reactions are thermodynamically favored at low temperatures. Addition reactions are thermodynamically favored at high temperatures. Addition reactions are thermodynamically favored at all temperatures.
Chemistry
2 answers:
Nookie1986 [14]3 years ago
8 0

Answer:

Addition reactions are thermodynamically favored at low temperatures.

Explanation:

kakasveta [241]3 years ago
5 0

Answer:

Addition reactions are thermodynamically favored at low temperatures.

Explanation:

Compared to substitutions or eliminations, addition reactions do not require to break as many bonds as them, as such, they do not require such a high input of energy (ie. temperature) in order to take place.

This is why if there's a high temperature, the reactions that require more energy -like substitutions or eliminations- will be more thermodinamically favored than the reactions that require less energy -like additions-, and viceversa.

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How many moles of magnesium, Mg, are there in 4.75 grams of magnesium?
Nina [5.8K]
Molar mass Mg = 24.3 g/mol

1 mole mg ------------ 24.3 g
?? moles mg --------- 4.75 g

4.75 x 1 / 24.3 => 0.195 moles of Mg

hope this helps!
3 0
3 years ago
How many moles are in 29.5 grams of Ax?
JulsSmile [24]

The number of moles present in 29.5 grams of argon is 0.74 mole.

The atomic mass of argon is given as;

Ar = 39.95 g/mole

The number of moles present in 29.5 grams of argon is calculated as follows;

39.95 g ------------------------------- 1 mole

29.5 g ------------------------------ ?

= \frac{29.5}{39.95} \\\\= 0.74 \ mole

Thus, the number of moles present in 29.5 grams of argon is 0.74 mole.

<em>"Your question seems to be missing the correct symbol for the element" </em>

Argon = Ar

Learn more here:brainly.com/question/4628363

6 0
2 years ago
When a aqueous solution of a certain acid is prepared, the acid is dissociated. Calculate the acid dissociation constant of the
stepan [7]
<h2>K_a = \dfrac{[H^{+}] [A^{-}]}{[HA]}</h2>

Explanation:

  • When an aqueous solution of a certain acid is prepared it is dissociated is as follows-

        {\displaystyle {\ce {HA  ⇄  {H^+}+{A^{-}}}  }}

Here HA is a protonic acid such as acetic acid, CH_3COOH

  • The double arrow signifies that it is an equilibrium process, which means the dissociation and recombination of the acid occur simultaneously.
  • The acid dissociation constant can be given by -

        K_a = \dfrac{[H^{+}] [A^{-}]}{[HA]}

  • The reaction is can also be represented by Bronsted and lowry -

         \\{\displaystyle {\ce {{HA}+ H_2O} ⇄  [H_3O^+] [A^-]

  • Then the dissociation constant will be

        K_a = \dfrac{[H_3O^{+}] [A^{-}]}{[HA]}

Here, K_a is the dissociation constant of an acid.

6 0
3 years ago
5. What happens to the average kinetic energy of water molecules as water freezeslt decreases as the water absorbs energy from i
4vir4ik [10]
The correct answer among the choices listed above is option D. The average kinetic energy of water molecules as water freeze <span>decreases as water releases energy to its surroundings. Energy is released as the molecules go into a more condensed phase which is the solid.</span>
3 0
3 years ago
Read 2 more answers
A sample of gas has a volume of 100.0 L at 135°C. Assuming the pressure remains constant, what is the volume of the gas if its t
lina2011 [118]

Answer: 84.56L

Explanation:

Initial volume of gas V1 = 100L

Initial temperature T1 = 135°C

Convert temperature in Celsius to Kelvin

( 135°C + 273 = 408K)

Final temperature T2 = 72°C

( 72°C + 273= 345K)

Final volume V2 = ?

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

100L/408K = V2/345K

To get the value of V2, cross multiply

100L x 345K = V2 x 408K

34500 = V2 x 408K

V2.= 34500/408

V2 = 84.56L

Thus, the volume of the gas becomes 84.56 liters

8 0
3 years ago
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