A sample 0. 100 moles of a gas is collected at at STP . 2.24 is the volume of the gas in liters.
The STP means standard temperature and pressure.
At STP,
Temperature = 0 °C =273 K
Pressure = 1 atm
We get value of volume by using ideal gas equation,
PV = nRT
- P is the pressure of the gas = 1 atm
- V is the volume occupied by the gas = ?
- n is the number of the moles = 1 mole
- T is the temperature of the gas = 273 K or 0 °C
- R universal gas constant = 8.31 J/ mole × K
Calculation,
Since, one mole of a gas occupy 22.4 L volume at STP
So, for 0.1 mole volume occupy = 22.4L × 0.1 mole/1 mole = 2.24L
To learn more about volume at STP,
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Complete combustion of acetylene generated carbon dioxide and water. This can be represent by following reaction
2C2H2 + 5O2 → 4CO2 + 2H2O
(2 mole) (4 mole)
From the above balanced reaction, it can be seen that 2 mole of acetylene on complete combustion generates 4 moles of carbon dioxide
i.e. 2 mole of C2H2 ≡ 4 mole of CO2
∴ 1.3 mole of C2H2 ≡ (4 X 1.3)/2 = 2.6 mole of CO2
Now, 1 mole of CO2 = 44 g
∴ 2.6 mole of CO2 = (44 X 2.6) = 114.4 g
Thus, <span>114.4 grams of carbon dioxide are produced from the combustion of 1.3 moles of acetylene</span>
The Rivergate because you are basing the distance off of there
