Answer:
0.27 atm
Explanation:
<em>At 25ºC, Kp = 2.9 x 10⁻³ for the reaction NH₄OCONH₂(s) ⇌ 2 NH₃(g) + CO₂(g). In an experiment carried out at 25ºC, a certain amount of NH₄OCONH₂ is placed in an evacuated rigid container and allowed to come to equilibrium. Calculate the total pressure in the container at equilibrium.</em>
Step 1: Make an ICE chart
Solid and liquids are ignored in ICE charts.
NH₄OCONH₂(s) ⇌ 2 NH₃(g) + CO₂(g)
I 0 0
C +2x +x
E 2x x
Step 2: Write the pressure equilibrium constant expression (Kp)
Kp = [NH₃]² × [CO₂]
Kp = (2x)² × x
2.9 × 10⁻³ = 4 x³
x = 0.090 atm
Step 3: Calculate the pressures at equilbrium
pNH₃ = 2x = 2(0.090 atm) = 0.18 atm
pCO₂ = x = 0.090 atm
The total pressure is:
P = 0.18 atm + 0.090 atm = 0.27 atm
Following reaction arise between Br2 and Cl2
Br2 + Cl2 → 2BrCl
(1mole) (1mole) (2moles)
From above balanced reaction, it can be seen that 1 mole of Br2 reacts with 1 mole of Cl2 to form 2 mole of BrCl
Thus, when <span>2.74 mol Cl2 reacts with excess Br2, 2.74 X 2 = 5.48 moles of BrCl will be formed. </span>
99% sure its false
its arranged by atomic number now i believe
Answer:
529.2 N
Explanation:
As we have studied the first law of motion, which states that every action has some reaction, equal in magnitude but having an opposite direction.
The force that is acting on the student will be due to gravitational force, that is equal to his weight.
F=mg: 54kg x 9.8m/s^2 =529.2 N
So the weight of student is exerting downwards towards the stool and land. The stool will also exert a force on the student that will be equal in magnitude but opposite in direction, then it will be 529.2 N.
This is because the student is sitting in a constant state and all the weight is exerted on the stool.
Note: This answer is very generic supposing that all the weight of the student is on stool. But, if we suppose that student's legs are on floor so it means the force of gravity acting on the stool has become less because student's mass on stool is less. So the answer would be a force somehow less than 529.2 N. However, since the question asked normal force, it would be weight of student in general terms.
Hope it helps!
