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3 years ago

How many different elements are in the compound sodium carbonate

Chemistry

1 answer:

Alona [7]3 years ago

6 0

Answer:

There are 6 different elements in sodium carbonate

Explanation:

Na - sodium

C - carbon

O - oxygen

Since there are two atoms of Na and three atoms of O

i. e Na2CO3

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What is the amount of heat released by 1.00 gram of liquid water at 0°C when it changes to 1.00 gram of ice at 0°C?

QveST [7]

Answer:

334J/g

Explanation:

Data obtained from the question include:

Mass (m) = 1g

Specific heat of Fusion (Hf) = 334 J/g

Heat (Q) =?

Using the equation Q = m·Hf, we can obtain the heat released as follow:

Q = m·Hf

Q = 1 x 334

Q = 334J

Therefore, the amount of heat released is 334J

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3 years ago

Micronutrients can be classified based on the presence of ______ in their chemical structures. According to this classification

natali 33 [55]

Answer:

Carbon

Explanation:

Micronutrients include elements or groups needed by the body in order to survive. These elements or groups include vitamins and minerals. Micronutrients can be divided into four categories:

1. water-soluble vitamins

2. Fat-soluble vitamins

3. Macrominerals

4. Trace minerals

8 0

2 years ago

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If an unknown element didplays many extremly strong metallic properties, where is it most likely to be located on the periodic t

Ipatiy [6.2K]

This is late but for anyone else who needs it...It's D. Far left

4 0

3 years ago

What volume (in mL) of a 0.200 MHNO3 solution is required to completely react with 27.6 mL of a 0.100 MNa2CO3 solution according

ladessa [460]

Answer:

There is 27.6 mL of a 0.200 M HNO3 solution required

Explanation:

Step 1: The balanced equation is:

Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)

This means for 1 mole Na2CO3 consumed, there is consumed 2 mole of HNO3 and there is produced 2 moles of NaNO3, 1 mole of CO2 and 1 mole of H2O

Step 2: Calculating moles of Na2CO3

moles of Na2CO3 =volume of Na2CO3 * Molarity of Na2CO3

moles of Na2CO3 = 27.6 *10^-3 * 0.1 M = 0.00276 moles

Step 3: Calculating moles of HNO3

In the balanced equation, we can see that for 1 mole of Na2CO3 consumed, there are consumed 2 moles of HNO3.

So for 0.00276 moles consumed of Na2CO3, there are consumed 0.00552 moles of HNO3.

This means 0.00276 moles of the base Na2CO3 would react with 0.00552 moles of the acid HNO3

Step 4: Calculating the volume of HNO3

volume of HNO3 = moles of HNO3 / Molarity of HNO3

volume of HNO3 = 0.00552 moles / 0.200 M = 0.0276 L

0.0276 L = 27.6 ml

There is 27.6 mL of a 0.200 M HNO3 solution required

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3 years ago

The low-resolution mass spectrum of an unknown analgesic X had a molecular ion of 151. Possible molecular formulas include C7H5N

garik1379 [7]

Answer:

The molecular formula of X is C8H9NO2

Explanation:

Step 1: Data given

exact mass of 151.0640

Molar mass of C = 12 g/mol

Molar mass of H = 1.00783 g/mol

Molar mass of O = 15.9949 g/mol

Molar mass of N = 14.0031 g/mol

Step 2: Calculate molar mass of C7H5NO3

7*12 + 5*1.00783 + 14.0031 + 3*15.9949 = 151.02695 g/mol

Step 3: Calculate molar mass of C8H9NO2

8*12 + 9*1.00783 + 14.0031 + 2*15.9949 = 151.06337 g/mol

Step 4: Calculate molar mass of C10H17N

10*12 + 17*1.00783 + 14.0031 = 151.13621 g/mol

The molecular formula of X is C8H9NO2

3 0

2 years ago