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2 years ago

You have 100 grams of each fuel. How many moles of each fuel do you have?

Chemistry

1 answer:

attashe74 [19]2 years ago

5 0

Answer:

Formula of Mole is,

Mole = Mass / M.Mass

Mass is same for all compounds but M.Mass is different for all.

1. C₃H₈

Mole = 100 g / 44.1 g/mol

Mole = 2.27 moles

2. C₂H₆O

Mole = 100 g / 46.07 g/mol

Mole = 2.12 moles

3. C₃H₆O

Mole = 100 g / 58.08 g/mol

Mole = 1.72 moles

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What are the uses of polythene?

Crank

Polyethylene is synthesized from ethylene which is a compound derived from natural gas or petroleum. It’s essentially a thermoplastic, implying that it can be molten and remolded into the desired shape making it reusable and cost-effective. Of all the different kinds of plastics produced around the world, polyethylene is the most common and significant.

Polyethylene is manufactured in three different forms namely:

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Hope it helps you...

7 0

3 years ago

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The reaction 2NO(g)+O2(g)−→−2NO2(g) is second order in NO and first order in O2. When [NO]=0.040M, and [O2]=0.035M, the observed

Oksanka [162]

Answer:

(a) The rate of disappearance of $O_{2}$ is: $4.65*10^{-5}$ M/s

(b) The value of rate constant is: 0.83036 $M^{-2}s^{-1}$

(d) The rate will increase by a factor of 3.24

Explanation:

The rate of a reaction can be expressed in terms of the concentrations of the reactants and products in accordance with the balanced equation.

For the given reaction:

$2NO(g)+O_{2}->2NO_{2}$

rate = $-\frac{1}{2} \frac{d}{dt}[NO]$ = $-\frac{d}{dt}[O_{2}]$ = $\frac{1}{2}\frac{d}{dt}[NO_{2}]$ -----(1)

According to the question, the reaction is second order in NO and first order in $O_{2}$ .

Then we can say that, rate = k $[NO]^{2}[O_{2}]$ -----(2)

where k is the rate constant.

The rate of disappearance of NO is given:

$-\frac{d}{dt}[NO]$ = $9.3*10^{-5}$ M/s.

(a) From (1), we can get the rate of disappearance of $O_{2}$ .

Rate of disappearance of $O_{2}$ = $-\frac{d}{dt}[O_{2}]$ = (0.5)*( $9.3*10^{-5}$ ) M/s = $4.65*10^{-5}$ M/s.

(b) The rate of the reaction can be obtained from (1).

rate = $-\frac{1}{2} \frac{d}{dt}[NO]$ = (0.5)*( $9.3*10^{-5}$ )

rate = $4.65*10^{-5}$ M/s

The value of rate constant can be obtained by using (2).

rate constant = k = $\frac{rate}{[NO]^{2}[O_{2}]}$

k = $\frac{4.65*10^{-5}}{(0.040)^{2}(0.035)}$ = 0.83036 $M^{-2}s^{-1}$

k = $\frac{rate}{[NO]^{2}[O_{2}]}$

Substituting the units of rate as M/s and concentrations as M, we get:

$\frac{Ms^{-1} }{M^{3}}$ = $M^{-2}s^{-1}$

(d) The reaction is second order in NO. Rate is proportional to square of the concentration of NO.

$rate\alpha [NO]^{2}$

If the concentration of NO increases by a factor of 1.8, the rate will increase by a factor of $(1.8)^{2}$ = 3.24

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3 years ago

What does 10% humidity in a weather report indicate?

GalinKa [24]

Answer:

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Quizletwhat does the mucosa of the small intestine release in response to the acidic chyme?

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Cells and microorganisms are extremely complex

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3 years ago

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