During nuclear fission, great amounts of energy are produced from____.
Answer: Out of all the options presented above, the one that completes the statement and makes it true, is answer choice D) very small amounts of mass. Nuclear fission power does not produce carbon and also produces 12% of the world's power.
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Answer:
When liquid water reaches the freezing point, it expands. After placing a sealed glass container full of water into the freezer, we might expect it to freeze, expand, and either crack or shatter the glass.
Explanation:
Explanation:
Student A would be introducing more error. While student B is subtracting the actual filter paper used in the experiment, Student A is using the mass of a different filter paper, which may have a slightly different mass than the filter paper that was used. To avoid having to aacount for this, or introducing such an error, follow Student B in weighing the filter paper before adding the sand.
I hope this helps.
Answer:
photons are emitted per second in a
Watt microwave oven.
Explanation:
The expression for the power is:-
![Power=\frac{Energy}{Time}](https://tex.z-dn.net/?f=Power%3D%5Cfrac%7BEnergy%7D%7BTime%7D)
Also, ![E=n\times \frac{h\times c}{\lambda}](https://tex.z-dn.net/?f=E%3Dn%5Ctimes%20%5Cfrac%7Bh%5Ctimes%20c%7D%7B%5Clambda%7D)
Where,
n = the number of photons
h = Plank's constant having value ![6.626\times 10^{-34}\ Js](https://tex.z-dn.net/?f=6.626%5Ctimes%2010%5E%7B-34%7D%5C%20Js)
c = the speed of light having value ![3\times 10^8\ m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E8%5C%20m%2Fs)
= the wavelength of the light
So,
![Power=\frac{n}{Time}\times \frac{h\times c}{\lambda}](https://tex.z-dn.net/?f=Power%3D%5Cfrac%7Bn%7D%7BTime%7D%5Ctimes%20%5Cfrac%7Bh%5Ctimes%20c%7D%7B%5Clambda%7D)
Thus, the expression for photons per second is:-
![\frac{n}{Time}=\frac{Power\times \lambda}{h\times c}](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7BTime%7D%3D%5Cfrac%7BPower%5Ctimes%20%5Clambda%7D%7Bh%5Ctimes%20c%7D)
Given that:-
Power = 10³ Watt
( 1 cm = 0.01 m)
[/tex]
So,
![Photon/sec=\frac{10^{3}\times 0.148}{6.626\times 10^{-34}\times 3\times 10^8}=7.45\times 10^{26}](https://tex.z-dn.net/?f=Photon%2Fsec%3D%5Cfrac%7B10%5E%7B3%7D%5Ctimes%200.148%7D%7B6.626%5Ctimes%2010%5E%7B-34%7D%5Ctimes%203%5Ctimes%2010%5E8%7D%3D7.45%5Ctimes%2010%5E%7B26%7D)
photons are emitted per second in a
Watt microwave oven.
So first we need to know what the formulas are:
Methane: ![CH_{4}](https://tex.z-dn.net/?f=%20CH_%7B4%7D%20)
Oxygen: ![O_{2}](https://tex.z-dn.net/?f=%20O_%7B2%7D%20)
Carbon Dioxide: ![CO_{2}](https://tex.z-dn.net/?f=%20CO_%7B2%7D%20)
Water: ![H_{2}O](https://tex.z-dn.net/?f=%20H_%7B2%7DO%20)
So then we follow the equation as specified in the question. Note that it does not need to be balanced, as the question states it wants the unbalanced equation:
→ ![CO_{2}+H_{2}O](https://tex.z-dn.net/?f=%20%20CO_%7B2%7D%2BH_%7B2%7DO%20)
This is the preliminary, unbalanced equation with the correct chemical formulas.