Answer:
Magnitude of work done W = 2.214 kW.
Explanation:
Given :
Mass of object , m = 16 kg.
Angle from horizon ,
.
Force applied , F = 188 N.
Displacement of block , D = 96.1 m.
Coefficient of kinetic friction ,
.
Component of force, required to move the block, 
Also , frictional force , 
We know, work done ,
( Here
, because the direction of displacement is opposite the direction of frictional force .)
Putting all value in above equation :
We get , 
Magnitude of work done W = 2.214 kW.
Hence, this is the required solution.