Answer:
Explanation:
given,


vector product 
= 
now, expanding the vector
the vector product is equal to
potential, kinetic, elastc energies
Answer:
The tension of the string is 41.876 N
Explanation:
Given;
length of the string, L = 2.11 m
mass of the string, m = 19.5 g = 0.0195 kg
frequency of the wave, f = 440 Hz
wavelength, λ = 15.3 cm = 0.153 m
The velocity of the wave is given by;
v = fλ
v = 440 x 0.153
v = 67.32 m/s
Also the velocity of the wave is given by

where;
μ is mass per unit length = 0.0195 / 2.11 = 0.00924 kg/m
T is the tension of the string
T = v²μ
T = (67.32)²(0.00924)
T = 41.876 N
Therefore, the tension of the string is 41.876 N
C because mass is how much space an object takes up
Answer:
P₃ > P₁ > P₂
Explanation:
To rank pressure of the given situation
a) we know
Pressure at height h below
P = ρ g h
density of salt water, ρ = 1029 kg/m³
P₁ = 1029 x 10 x 0.2
P₁ = 2058 Pa
b) density of fresh water, ρ = 1000 kg/m³
P₂ = 1000 x 10 x 0.2
P₂ = 2000 Pa
c) density of mercury, ρ = 13593 kg/m³
P₃ = 13593 x 10 x 0.05
P₃ = 6796.5 Pa
Rank of Pressures from highest to lowest
P₃ > P₁ > P₂