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wolverine [178]
4 years ago
12

When is the data considered valid

Physics
1 answer:
dexar [7]4 years ago
4 0
Data’s conclusion is considered valid if the experiment validity is being controlled. With this conclusion validity, our data gathered and presented are considered a reasonable one. It is the most important types of validity. As what is said, by having conclusion validity, your data will be undoubtedly least considered since it is labelled as statistical and well-studied. Once you already mention the word statistics meaning it is studied and surveyed with the most of the human race and includes relationship in your data.



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Un hombre parado en el techo de un edificio, tira una bola verticalmente hacia arriba con una velocidad de 12m/s, la bola llega
zmey [24]

Respuesta:

24m

Explicación:

Según la ecuación de movimiento

v = u + en

Dado

Velocidad final v = 12 m / s

velocidad inicial u = 0 m / s

tiempo t = 4s

Sustituir

12 = 0 + 4a

a = 12/4

a = 3 m / s²

Lo siguiente es obtener la distancia;

S = ut + 1 / 2at²

S = 0 (4) + 1/2 (3) (4) ²

S = 3 * 16/2

S = 48/2

S = 24 m

Por lo tanto, la distancia requerida es de 24 m.

4 0
3 years ago
vA 61.2-kg circus performer is fired from a cannon that is elevated at an angle of 57.8 ° above the horizontal. The cannon uses
dsp73

Answer:

The effective spring constant of the firing mechanism is 1808N/m.

Explanation:

First, we can use kinematics to obtain the initial velocity of the performer. Since we know the angle at which he was launched, the horizontal distance and the time in which it's traveled, we can calculate the speed by:

v_0_x=\frac{x}{t}\\ \\v_0\cos\theta=\frac{x}{t}\\\\v_0=\frac{x}{t\cos\theta}

(This is correct because the horizontal motion has acceleration zero). Then:

v_0=\frac{20.8m}{(2.60s)\cos57.8\°}\\\\v_0=15.0m/s

Now, we can use energy to obtain the spring constant of the firing mechanism. By the conservation of mechanical energy, considering the instant in which the elastic band is at its maximum stretch as t=0, and the instant in which the performer flies free of the bands as final time, we have:

E_0=E_f\\\\U_e=K\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\\implies k=\frac{mv^2}{x^2}

Then, plugging in the given values, we obtain:

k=\frac{(61.2kg)(15.0m/s)^2}{(2.76m)^2}\\\\k=1808N/m

Finally, the effective spring constant of the firing mechanism is 1808N/m.

3 0
3 years ago
In a football game, running back is at the 10-yard line and running up the field towards the 50 yard
kotykmax [81]

Answer:

34 yards or 34 yard line

Explanation:

8 × 3 = 24

24 + 10 = 34

8 0
3 years ago
Which of the Materials are conductors?(select all apply)
Alex73 [517]

Answer:

mechanical pencil lead

iron

silver

brass

copper

yarn

3 0
3 years ago
Assuming that the smallest measurable wavelength in an experiment is 0.950 fm , what is the maximum mass of an object traveling
Arada [10]

Answer:

The maximum mass is 2.89x10^{-21}Kg

Explanation:

The wavelength of the electron can be determined by means of the De Broglie equation.

\lambda = \frac{h}{p} (1)

Where h is the Planck's constant and p is the momentum.

\lambda = \frac{h}{mv}  

m = \frac{h}{\lambda v}  (2)

Where m is the mass and v is the velocity.

Before using equation 2 it is necessary to express the wavelength from femtometers to meters.

\lambda = 0.950fm .\frac{1m}{1x10^{15}fm} -- 9.5x10^{-16}m

Finally, equation 2 can be used.

m = \frac{6.624x10^{-34} J.s}{(9.5x10^{-16}m)(241m/s)}

But 1J = Kg.m^{2}/s^{2}

m = \frac{6.624x10^{-34} Kg.m^{2}/s^{2}.s}{(9.5x10^{-16}m)(241m/s)}

m = 2.89x10^{-21}Kg    

Hence, the maximum mass is 2.89x10^{-21}Kg

6 0
3 years ago
Read 2 more answers
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