Answer:
B. 0.42
Explanation:
Since the two alleles are at Hardy-Weinberg equilibrium, the sum of the frequency of two alleles will be one. If the frequency of a dominant allele is "p" and that of the recessive allele is "q", then p+q=1
According to the given information, the frequency of one allele in the population is= 0.7
This means that the frequency of the other allele would be= 1-0.7 = 0.3
Frequency of heterozygote in the population =2pq = 2 x 0.7 x 0.3 = 0.42
The two major surviving clades of diapsids include modern animals like snakes, lizards, crocodiles, and birds
A clade is a branch in a cladogram that has a single common ancestor with all of its offspring. An evolutionary tree that depicts the relationships between species' ancestors is called a cladogram. In the past, cladograms were created using similarities among species' phenotypic or physical characteristics.
All hominoids, including humans, chimpanzees, gorillas, orangutans, and gibbons, are members of this group. The Hominoid clade is a subgroup of the Anthropoids, a broader clade that includes Old World and New World monkeys. The use of a phylogenetic tree makes clade identification simple. Just visualize pruning even one branch from the tree.
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Answer:
Zero (0)
Explanation:
According to the given information the genotype of the woman with blood type "AB" would by I^AI^B. The genotype of the man with blood type O would be "ii". Here, the alleles I^A and I^B are dominant over the allele "i".
A cross between parents with genotype I^AI^B and ii would give 50% of children with I^Ai genotype and 50% of children with I^Bi genotype. The children with "I^Ai genotype" would have blood type "A" and the children with I^Bi genotype would have blood type "B". This couple is never likely to have any child with blood type "O" since the mother does not carry allele "i".
Cross: I^AI^B x ii = 1/2 I^Ai : 1/2 I^Bi
Answer:
B
Explanation:
Water, sunlight and amount of oxygen in water