Let x be a random variable that represents checkout time (time spent in the actual checkout process) in minutes in the express l
ane of a large grocery. Based on a consumer survey, the mean of the x distribution is about μ = 2.7 minutes, with standard deviation σ = 0.6 minute. Assume that the express lane always has customers waiting to be checked out and that the distribution of x values is more or less symmetric and mound-shaped. What is the probability that the total checkout time for the next 30 customers is less than 90 minutes? Let us solve this problem in steps.
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Answer:
Answer:
164.32 earth year
Step-by-step explanation:
distance of Neptune, Rn = 4.5 x 10^9 km
distance of earth, Re = 1.5 x 10^8 km
time period of earth, Te = 1 year
let the time period of Neptune is Tn.
According to the Kepler's third law
T² ∝ R³
Tn = 164.32 earth years
Thus, the neptune year is equal to 164.32 earth year.
Step-by-step explanation: