Let x be a random variable that represents checkout time (time spent in the actual checkout process) in minutes in the express l
ane of a large grocery. Based on a consumer survey, the mean of the x distribution is about μ = 2.7 minutes, with standard deviation σ = 0.6 minute. Assume that the express lane always has customers waiting to be checked out and that the distribution of x values is more or less symmetric and mound-shaped. What is the probability that the total checkout time for the next 30 customers is less than 90 minutes? Let us solve this problem in steps.
1 answer:
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Answer:
y = 0.008x^2 + 0.518x + 131.886
Step-by-step explanation:
- Make sure your Plot 1 is ON. Select the Scatter Plots and the appropriate lists.
- Clear all functions in [Y=]
- Input data in L1 and L2. Go to [Stat] [Enter] to input data.
- Graph data points. ...
- Choose a regression from the list in [Stat] "CALC". ...
- Go to [ZOOM] "9: ZoomSTat" to view the data with the regression curve.
(credit: CPM Educational Program)
