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kati45 [8]
3 years ago
10

If the initial amount of iodine-131 is 537 grams , how much is left after 10 days?

Mathematics
1 answer:
viktelen [127]3 years ago
4 0

Answer:

225.78 grams

Step-by-step explanation:

To solve this question, we would be using the formula

P(t) = Po × 2^t/n

Where P(t) = Remaining amount after r hours

Po = Initial amount

t = Time

In the question,

Where P(t) = Remaining amount after r hours = unknown

Po = Initial amount = 537

t = Time = 10 days

P(t) = 537 × 2^(10/)

P(t) = 225.78 grams

Therefore, the amount of iodine-131 left after 10 days = 225.78 grams

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<h2><em><u>Answer:</u></em></h2>

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