$\text{Let}\\\\k:y=m_1x+b_1\\\\l:y=m_2x+b_2\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\=========================$

$\text{We have}\ y=\dfrac{1}{5}x+10\to m_1=\dfrac{1}{5}\\\\\text{Therefore}\ m_2=-\dfrac{1}{\frac{1}{5}}=-5.\\\\\text{Put the value of a slope and the coordinates of the point (-3, 5)}\\\text{to the equation}\ y=mx+b:\\\\5=-5(-3)+b\\5=15+b\qquad\text{subtract 15 from both sides}\\-10=b\to b=-10\\\\\text{Finally:}\\\\y=-5x-10$

7 0

3 years ago

Solve the system of equations.

Tom [10]

Easiest method you can apply (Cramer's one). "Thanks me" if i've been helpful

6 0

3 years ago

Which logarithmic equation is equivalent to the exponential equation below? E^a=60

Gala2k [10]

Answer:

Step-by-step explanation:

e is the base of the natural log system.

take the natural log of both sides.

ln(e^a) = ln(60) The power can come down

a ln(e) = ln(60) The natural log of e = 1

a * 1 = ln (60)

a = ln(60)

8 0

3 years ago

Please help I am confused.

nignag [31]

Answer:

9 cm, C

11 cm, B

14 cm A

Step-by-step explanation:

7 0

2 years ago