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Assoli18 [71]
3 years ago
6

What is the freezing point (in C) of a 1.56 m aqueous solution of CaCl2? (Amount to three decimal points)

Chemistry
2 answers:
Julli [10]3 years ago
4 0
Supposing complete ionization: 
<span>CaCl2 → Ca{2+} + 2 Cl{-} [three ions total] </span>

<span>(1.56 m CaCl2) x (3 mol ions / 1 mol CaCl2) = 4.68 m ions </span>

<span>(1.86 °C/m) x (4.68 m) = 8.70 °C change </span>

<span>0°C - 8.70°C = - 8.70°C</span>
Bogdan [553]3 years ago
4 0

The answer that was correct for me was 25.687 degrees C

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irina1246 [14]

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