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GREYUIT [131]
3 years ago
15

As a student , what can you do to help in preventing pollution in your community ?​

Chemistry
1 answer:
aliya0001 [1]3 years ago
3 0

Answer: as a student , i will  do to help in preventing pollution in my  community :

Reduce the number of trips you take in your car.

Reduce or eliminate fireplace and wood stove use.

Avoid burning leaves, trash, and other materials.

Avoid using gas-powered lawn and garden equipment.

Using non-toxic or less toxic chemicals as cleaners, degreasers and other maintenance chemicals. Implementing water and energy conservation practices. Reusing materials such as drums and pallets rather than disposing of them as waste.

Store your household chemicals (including cleaning products, paints, fuel canisters, etc.) as far away as possible from the living space and, if possible, in metal cabinets. Do not store chemicals in areas where you spend most of the time. Also, do not store chemicals in open cabinets or shelves.

Use Public Transportation. Use your vehicle a lot less often. .

Drive Smart. .

Do Regular Car Check-Up. .

Keep Car Tires Properly Inflated. .

Buy Energy-Efficient Vehicles. .

Consider “going green” .

Plant a Garden. .

Use Low-VOC or Water-based Paints.

Avoid smoking indoors (but quitting smoking is the best answer for overall health).

Use craft supplies in well-ventilated areas.

Make sure your gas stove is well-ventilated.

Minimize clutter.

Remove carpeting if possible.

Use a dehumidifier and/or air conditioner to reduce moisture.

How can students help reduce pollution?

Help Recycling

The most obvious things to reuse are plastic, glass, metal, and paper or fabric (paper and organic fabric are made of the same component, cellulose, and are recycled in a similar way). The color-coded trash bins show where each of these components can be put to be recycled in a proper way.

REDUSE ,REUSE , RECYCLE

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Answer:

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Explanation:

This is the equilibrium:

                 2NH₃(g)   ⇄     N₂(g)     +     3H₂(g)

Initially       0.0733

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Eq     0.0733 - 0.0733α    α/2                0.103

We introduced 0.0733 moles of ammonia, initially. So in the reaction "α" amount react, as the ratio is 2:1, and 2:3, we can know the moles that formed products.

Now we were told that in equilibrum we have a [H₂] of 0.103, so this data can help us to calculate α.

3/2α = 0.103

α = 0.103 . 2/3 ⇒ 0.0686

So, concentration in equilibrium are

NH₃ = 0.0733 - 0.0733 . 0.0686 = 0.0682

N₂ = 0.0686/2 = 0.0343

So this moles, are in a volume of 1L, so they are molar concentrations.

Let's make Kc expression:

Kc= [N₂] . [H₂]³ / [NH₃]²

Kc = 0.0343 . 0.103³ / 0.0682² = 8.05x10⁻³

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