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GREYUIT [131]
3 years ago
15

As a student , what can you do to help in preventing pollution in your community ?​

Chemistry
1 answer:
aliya0001 [1]3 years ago
3 0

Answer: as a student , i will  do to help in preventing pollution in my  community :

Reduce the number of trips you take in your car.

Reduce or eliminate fireplace and wood stove use.

Avoid burning leaves, trash, and other materials.

Avoid using gas-powered lawn and garden equipment.

Using non-toxic or less toxic chemicals as cleaners, degreasers and other maintenance chemicals. Implementing water and energy conservation practices. Reusing materials such as drums and pallets rather than disposing of them as waste.

Store your household chemicals (including cleaning products, paints, fuel canisters, etc.) as far away as possible from the living space and, if possible, in metal cabinets. Do not store chemicals in areas where you spend most of the time. Also, do not store chemicals in open cabinets or shelves.

Use Public Transportation. Use your vehicle a lot less often. .

Drive Smart. .

Do Regular Car Check-Up. .

Keep Car Tires Properly Inflated. .

Buy Energy-Efficient Vehicles. .

Consider “going green” .

Plant a Garden. .

Use Low-VOC or Water-based Paints.

Avoid smoking indoors (but quitting smoking is the best answer for overall health).

Use craft supplies in well-ventilated areas.

Make sure your gas stove is well-ventilated.

Minimize clutter.

Remove carpeting if possible.

Use a dehumidifier and/or air conditioner to reduce moisture.

How can students help reduce pollution?

Help Recycling

The most obvious things to reuse are plastic, glass, metal, and paper or fabric (paper and organic fabric are made of the same component, cellulose, and are recycled in a similar way). The color-coded trash bins show where each of these components can be put to be recycled in a proper way.

REDUSE ,REUSE , RECYCLE

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A bomb calorimeter has a heat capacity of 783 J/oC and contains 254 g of water whose specific heat capacity is 4.184 J/goC. How
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Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

q=[q_1+q_2]

q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]

where,

q = heat released by the reaction

q_1 = heat absorbed by the calorimeter

q_2 = heat absorbed by the water

c_1 = specific heat of calorimeter = 783J/^oC

c_2 = specific heat of water = 4.184J/g^oC

m_2 = mass of water = 254 g

\Delta T = change in temperature = T_2-T_1=(23.73-26.01)=-2.28^oC

Now put all the given values in the above formula, we get:

q=[(783J/^oC\times -2.28^oC)+(254g\times 4.184J/g^oC\times -2.28^oC)]

q=-4208.28J=-4.81kJ

Therefore, the amount of heat evolved by a reaction is, 4.81 kJ

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