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2 years ago

Toothpaste contains Sodium fluoride which is used to prevent tooth decay. How many grams are in 1 mole NaF?

Chemistry

1 answer:

nikitadnepr [17]2 years ago

6 0

The answer is 42 grams of NaF are there in 1 mole.

A mole is defined as 6.022 × 10²³ atoms, molecules, ions, or other chemical units.

and the molar mass of a substance is defined as the mass of 1 mole of that substance, expressed in grams per mole.

It is equal to the mass of 6.022 × 10²³ atoms, molecules, or formula units of that substance.

Molar Mass , i.e. mass of 1 mole of NaF is sum of molar mass of Na and F

23 + 19

42 grams

Therefore 42 grams of NaF Sodium-fluoride are there in 1 mole.

To know more about mole

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Which equation shows how wavelength is related to velocity and frequency?

Nataly_w [17]

Answer:

The correct option is the option;

$\lambda = \dfrac{v}{f}$

Explanation:

The wavelength of a wave is the distance between two successive crests of the wave

Therefore, the wavelength, λ, is given by the fraction of the velocity, <em>v</em>, of the wave divided by the frequency, <em>f</em>, (the number of cycles that pass through a point) of the wave

Mathematically, we have;

$The \ wavelength, \ \lambda = \dfrac{The \ wave \ velocity, \ v}{The \ wave \ frequency, \ f}$

$\lambda = \dfrac{v}{f}$

4 0

3 years ago

Which would be the best way to represent the concentration of a 1. 75 M K2CrO4 solution? 1. 75% K2CrO4 [K2CrO4] (K2CrO4) K2CrO4,

tekilochka [14]

The amount of the solute present in the given solution is called the concentration. The best way to represent the concentration of the solution is $\rm [K_{2}CrO_{4}].$

<h3>What is molar concentration?</h3>

Molar concentration is the molarity of the solution that is the measure of the concentration of the solute dissolved in the solution.

The formula for calculating molar concentration is given as,

$\rm Molarity = \dfrac{\text{moles of solute}}{\text{Solution in L}}$

The concentration of any substance is represented in the square bracket like $\rm [X]$ or $\rm [K_{2}CrO_{4}].$

Therefore, option B. $\rm [K_{2}CrO_{4}]$ is the representation of the concentration.

Learn more about the molarity here:

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8 0

2 years ago

Can you help me balance the equations from 1-10 please and thank you.

Korolek [52]

Answer:

2 NaBr + Ca(OH)2 → CaBr2 + 2NaOH
2 NH3 +H2SO4 → (NH4)2(SO4)

8 0

3 years ago

What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig

Mashutka [201]

Answer:

$P_H =2.86$

$c=1.4\times 10^{-4}$

Explanation:

first write the equilibrium equaion ,

$C_3H_6O_3$ ⇄ $C_3H_5O_3^{-} +H^{+}$

assuming degree of dissociation $\alpha$ =1/10;

and initial concentraion of $C_3H_6O_3$ =c;

At equlibrium ;

concentration of $C_3H_6O_3 = c-c\alpha$

$[C_3H_5O_3^{-} ]= c\alpha$

$[H^{+}] = c\alpha$

$K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}$

$\alpha$ is very small so $1-\alpha$ can be neglected

and equation is;

$K_a = {c\alpha \times \alpha}$

$[H^{+}] = c\alpha$ = $\frac{K_a}{\alpha}$

$P_H =- log[H^{+} ]$

$P_H =-logK_a + log\alpha$

$K_a =1.38\times10^{-4}$

$\alpha = \frac{1}{10}$

$P_H= 3.86-1$

$P_H =2.86$

composiion ;

$c=\frac{1}{\alpha} \times [H^{+}]$

$[H^{+}] =antilog(-P_H)$

$[H^{+} ] =0.0014$

$c=0.0014\times \frac{1}{10}$

$c=1.4\times 10^{-4}$

6 0

3 years ago

1. In which of these forms does acid precipitation reach the surface of<br><br> Earth?

vodomira [7]

Answer:

Wet deposition

Explanation:

when the chemicals produced in the Earth can evaporate and reach the clouds, it will mixed with the water inside the clouds and form a slightly acid water than when is time to deposit the water into the Earth as snow, rain, fog or mist, the chemicals will travel with the water dissolved in it.

When they reach the soil, eventually, the water will evaporate or will be absorbed by soil, so the chemicals that are left behind, will reach the surface of Earth.

Depending where the chemicals were deposit, they can contaminate the sea, or other water bodies, or soil areas of crops, buildings, etc.

Hope this info is useful.

5 0

3 years ago