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3 years ago

(2x - 3y)(4x - y) can you help me

Mathematics

2 answers:

professor190 [17]3 years ago

5 0

You must FOIL (first, outside, inside, last)

First (The first number/variable of each parentheses must be multiplied together)

(2x - 3y)(4x - y)

$8x^{2}$

Outside (The outside number/variable of each parentheses must be multiplied together)

(2x - 3y)(4x - y)

-2xy

Inside (The inside number/variable of each parentheses must be multiplied together)

(2x - 3y)(4x - y)

-12xy

Last (The last number/variable of each parentheses must be multiplied together)

(2x - 3y)(4x - y)

$3y^{2}$

Now add/subtract each FOIL answer according to its sign

$8x^{2}$ - 2xy - 12xy + $3y^{2}$

Combine like terms

$8x^{2}$ + $3y^{2}$ - 14xy

Hope this helped!

~Just a girl in love with Shawn Mendes

Mnenie [13.5K]3 years ago

3 0

Answer:

Step-by-step explanation:

Use FOIL: <em>(a + b)(c + d) = ac + ad + bc + bd</em>

(2x - 3y)(4x - y) = (2x)(4x) + (2x)(-y) + (-3y)(4x) + (-3y)(-y)

= 8x² - 2xy - 12xy + 3y²

<em>combine like terms</em>

= 8x² + (-2xy - 12xy) + 3y² = 8x² - 14xy + 3y²

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A machinist drilled a conical hole into a cube of metal as shown.

Mnenie [13.5K]

Answer:

512ft³

Step-by-step explanation:

If the cube its sides of all 8 feet, then the length, width, and height is 8 feet. Then, multiply 8 by 8 you get 64 and then multiply 64 by 8 to get 512.

7 0

3 years ago

The Jurassic Zoo charges $13 for each adult admission and $4 for each child . The total bill for the 238 people from a school tr

slava [35]

Answer:

42 adults and 196 children went to the zoo

Step-by-step explanation:

Let

x ----> the number of adults

y ----> the number of children

we know that

The total bill for the 238 people from a school trip was $1330

$x+y=238$ ----> equation A

$13x+4y=1,330$ ----> equation B

Solve the system of equations by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

the solution is the point (42,196)

see the attached figure

therefore

42 adults and 196 children went to the zoo

6 0

3 years ago

Write out the form of the partial fraction decomposition of the function. Do not determine the numerical values of the coefficie

Dvinal [7]

For part (a), you have

$\dfrac x{x^2+x-6}=\dfrac x{(x+3)(x-2)}=\dfrac a{x+3}+\dfrac b{x-2}$
$x=a(x-2)+b(x+3)$

If $x=2$ , then $2=b(2-3)\implies b=-2$ .

If $x=-3$ , then $-3=a(-3-2)\implies a=\dfrac35$ .

So,

$\dfrac x{x^2+x-6}=\dfrac 3{5(x+3)}-\dfrac 2{x-2}$

For part (b), since the degrees of the numerator and denominator are the same, you first need to find the quotient and remainder upon division.

$\dfrac{x^2}{x^2+x+2}=\dfrac{x^2+x+2-x-2}{x^2+x+2}=1-\dfrac{x+2}{x^2+x+2}$

In the remainder term, the denominator $x^2+x+2$ can't be factorized into linear components with real coefficients, since the discriminant is negative $(1-4\times1\times2=-7)$ . However, you can still factorized over the complex numbers, so a partial fraction decomposition in terms of complexes does exist.

$x^2+x+2=0\implies x=-\dfrac12\pm\dfrac{\sqrt7}2i$
$\implies x^2+x+2=\left(x-\left(-\dfrac12+\dfrac{\sqrt7}2i\right)\right)\left(x-\left(-\dfrac12-\dfrac{\sqrt7}2i\right)\right)$
$\implies x^2+x+2=\left(x+\dfrac12-\dfrac{\sqrt7}2i\right)\left(x+\dfrac12+\dfrac{\sqrt7}2i\right)$

Then you have

$\dfrac{x+2}{x^2+x+2}=\dfrac a{x+\dfrac12-\dfrac{\sqrt7}2i}+\dfrac b{x+\dfrac12+\dfrac{\sqrt7}2i}$
$x+2=a\left(x+\dfrac12+\dfrac{\sqrt7}2i\right)+b\left(x+\dfrac12-\dfrac{\sqrt7}2i\right)$

When $x=-\dfrac12-\dfrac{\sqrt7}2i$ , you have

$-\dfrac12-\dfrac{\sqrt7}2i+2=b\left(-\dfrac12-\dfrac{\sqrt7}2i+\dfrac12-\dfrac{\sqrt7}2i\right)$
$\dfrac32-\dfrac{\sqrt7}2i=-\sqrt7ib$
$b=\dfrac12+\dfrac3{2\sqrt7}i=\dfrac1{14}(7+3\sqrt7i)$

When $x=-\dfrac12+\dfrac{\sqrt7}2i$ , you have

$-\dfrac12+\dfrac{\sqrt7}2i+2=a\left(-\dfrac12+\dfrac{\sqrt7}2i+\dfrac12+\dfrac{\sqrt7}2i\right)$
$\dfrac32+\dfrac{\sqrt7}2i=\sqrt7ia$
$a=\dfrac12-\dfrac3{2\sqrt7}i=\dfrac1{14}(7-3\sqrt7i)$

So, you could write

$\dfrac{x^2}{x^2+x+2}=1-\dfrac{x+2}{x^2+x+2}=1-\dfrac {7-3\sqrt7i}{14\left(x+\dfrac12-\dfrac{\sqrt7}2i\right)}-\dfrac {7+3\sqrt7i}{14\left(x+\dfrac12+\dfrac{\sqrt7}2i\right)}$

but that may or may not be considered acceptable by that webpage.

5 0

3 years ago

Read 2 more answers

What is the GCF of the terms of 8x3 − 12x2 + 4x?

svetoff [14.1K]

I think the GCF is 4x in not sure olz tell me if i'm wrong

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3 years ago

? Help

svlad2 [7]

Answer:

Step-by-step explanation: