200.00 grams of an organic compound is known to contain 83.884 grams of carbon, 10.486
1 answer:
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If 0.400 moles CO and 0.400 moles O2 completely react, 17.604 grams of CO2 would be produced.
First, let us look at the balanced equation of reaction:
According to the equation, the mole ratio of CO and O2 is 2:1. But in reality, the mole ratio supplied is 1:1. Thus, CO is the limiting reactant while O2 is in excess.
Also from the equation, the ratio of CO consumed to that of CO2 produced is 1:1. Thus, 0.400 moles of CO2 would also be produced from 0.400 moles of CO.
Recall that: mole = mass/molar mass
Therefore, the mass in grams of CO2 that would be produced from 0.400 moles can be calculated as:
Mass = mole x molar mass
= 0.400 x 44.01
= 17.604 grams
More on calculating mass from number of moles can be found here: brainly.com/question/12513822
Answer:
m = 0.659 ounce
Explanation:
It is given that,
The thickness of a Teflon coating is, d = 1 mm
Area of the coating, A = 36 inch²
The density of Teflon, d = 0.805 g/mL
We need to find ounces of Teflon are needed.
Firstly, find the volume of the Teflon needed,
1 inch² = 6.4516 cm²
36 inch² = 232.258 cm²
Density,
V is volume of the Teflon needed, V = Ad
So,
Also, 1 gram = 0.035274 ounce
18.69 gram = 0.659 ounce
So, 0.659 ounces of Teflon are needed.