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Advocard [28]
4 years ago
9

Mrs. Barto has a pet rabbit and wants to build a pen for it. She has 3 pieces of lumber: one is 3 ft, one is 7 ft, and the other

is 8 ft long. Can she build a closed triangular pen with these three boards (will the boards form a triangle)?
Mathematics
1 answer:
sammy [17]4 years ago
6 0

Answer:

Yes, it is possible

Step-by-step explanation:

In a triangle, the length of the longest side of the triangle cannot be larger than the sum of the lenghts of the two shortest sides.

In formula, this means that:

c\leq a+b

where

c is the length of the longest side

a, b are the lengths of the shortest side

In this problem, we want to build a triangle using 3 pieces of lumber, each of length:

a = 3 ft

b = 7 ft

c = 8 ft

We can verify that the length of the longest piece of lumber is less than the sum of the lengths of the other two sides, so:

8\leq 3+7 = 10

Therefore, yes, it is possible to build a closed triangular pen.

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Convert 12 and a half of 30
tamaranim1 [39]

Answer:

375

Step-by-step explanation:

12½[30] → 25⁄2[30]

Multiply 25 by 30 [750] then divide by 2 to get 375.

I am joyous to assist you anytime.

7 0
4 years ago
Find the average of e^-x over [0,3]
yaroslaw [1]

The average value of a continuous function <em>f(x)</em> over an interval [<em>a</em>, <em>b</em>] is given by the integral,

\displaystyle \frac1{b-a}\int_a^b f(x)\,\mathrm dx

Compute the integral for <em>f(x)</em> = <em>e</em> ⁻ˣ over [0, 3] :

\displaystyle \frac1{3-0}\int_0^3e^{-x}\,\mathrm dx=\frac13(-e^{-x})\bigg|_0^3=\frac13(-e^{-3}-(-e^{-0})) = \frac13 \left(1-\frac1{e^3}\right) = \boxed{\frac{e^3-1}{3e^3}}

8 0
3 years ago
The diagram shows a circle of radius 1 contained in a square. If the area of the circle equals x% of the area of the square, the
11111nata11111 [884]

Answer:

Area of square  with a side of 2r  = 2(1)  = 2  = 2^2   = 4

Area of circle =  pi ( 1)^2  =  pi

x =  pi / 4   ≈  .79   =  79%

7 0
3 years ago
class size m average 0.82 n class n average 0.78. if the average for combined classes is 80%, what is relationship between m and
katen-ka-za [31]

Answer:

The relation between m and n is ,  m = n      

Step-by-step explanation:

Given as :

The average for n class  = 0.82 = 82%

The average for m class  = 0.78 = 78%

The average for ( m + n ) class  = 80%

So , \frac{x_1 +x_2+x_3+x_4+ ....... + x_n}{n} = 82%

And \frac{x_1 +x_2+x_3+x_4+ ....... + x_m}{m} = 78%

And , \frac{(x_1+x_2+x_3+x_4+ ......+x_n ) + (x_1+x_2+x_+x_4+.....+x_m)}{m+n} = 80%

So , 0.82×n + 0.78×m = 0.80× (m+n)

Or,  0.82×n - 0.80×n = 0.80×m -   0.78×m

Or,   0.02×n              =  0.02×m

Or,   \frac{m}{n} =  \frac{0.02}{0.02}

∴      \frac{m}{n} = 1

I.e     m  =  n

Hence The relation between m and n is ,  m = n      Answer

6 0
3 years ago
A boat travels at constant speed. After 20 minutes the boat had traveled 2.5 miles. How long does it take the boat to reach the
schepotkina [342]

120 minutes

Step by step:

divide 20 by 2.5 to find how many minutes it takes to drive 1 mile, then multiply that by 15 miles

7 0
4 years ago
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