PLEASE HELP ME I WILL GIVE BRAINLIEST!!!!

9. A ladder of length 23 feet leans against the side of a building. The angle of elevation of the ladder is 76. Find the distanc

irakobra [83]

<h3>Answer:</h3>

B) 22.32 feet

$\quad\rule{300pt}{1pt}$

<h3>Solution:</h3>

we are given that , a ladder is placed against a side of building , which forms a right angled triangle . We wre given one side of a right angled triangle ( hypotenuse ) as 23 feet and the angle of elevation as 76 ° . We can find the Perpendicular distance from the top of the ladder go to the ground by using the trigonometric identity:

$\qquad\quad\bull ~{\boxed{\bf{ Sin\theta =\dfrac{Perpendicular}{Hypotenuse}}} }~\bull$

Here,

hypotenuse = 23 feet
$\theta$ = 76°
Value of Sin $\theta$ = 0.97
Perpendicular = ?

$\quad\dashrightarrow\quad \sf { sin\theta =\dfrac{P}{H}}$

$\quad\dashrightarrow\quad \sf { sin76° =\dfrac{P}{23}}$

$\quad\dashrightarrow\quad \sf { 0.97=\dfrac{P}{23}}$

$\quad\dashrightarrow\quad \sf {P = 0.97 \times 23 }$

$\quad\dashrightarrow\quad \sf { P = 22.32}$

‎ㅤ‎ㅤ‎ㅤ~Hence, the distance from the top of the ladder to the ground is 22.32 feet !

$\rule{300pt}{2pt}$

4 0

2 years ago

Which of the following is the equation of a line parallel to the line y=-x+1 passing through the point (4,1)

Softa [21]

Y=-x+b

plug in x = 4 and y = 1 to find b

1 = -4 + b and we know that if you add 5 and -4 you get 1. So ...

5 = b so if we plug that in

y= -x + 5

which is the same as y + x = 5, So it would be A

6 0

3 years ago

Plss help me solve these 2 !!!!!!!!!!! for a brainlist ;))

lisabon 2012 [21]

Answer:

1. d

2. a

Step-by-step explanation:

Thats how it goes!

Branliest plzzz

3 0

2 years ago

1. Parallelogram WXYZ is shown on the coordinate plane ect... Added photo plz help!!

aliya0001 [1]

Answer:

Step-by-step explanation:

12.718 units

Step-by-step explanation:

The coordinates of the vertices of parallelogram WXYZ are given to be W(0,-1), X(4,0), Y(3,-2) and Z(-1,-3).

So, the perimeter of the parallelogram will be 2(WX + XY) {Since opposite sides of parallelogram are same in length}

Now, length of WX = units, To find the units click this link :

https://tex.z-dn.net/?f=%5Csqrt%7B(-1)%5E%7B2%7D%20%2B%204%5E%7B2%7D%20%7D%20%3D%20%5Csqrt%7B17%7D%20%3D%204.123

And, length of XY = units, To find the units click this link :

https://tex.z-dn.net/?f=%5Csqrt%7B(4-3)%5E%7B2%7D%20%2B%20(0-(-2))%5E%7B2%7D%7D%20%3D%20%5Csqrt%7B5%7D%20%3D%202.236

Therefore, the perimeter of the parallelogram WXYZ = 2(4.123 + 2.236) = 12.718 units. (Answer)

5 0

2 years ago

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further from the lighthouse. The new bearing is 25°

djverab [1.8K]

Answer:

The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.

Step-by-step explanation:

The question is incomplete. The complete question should be

The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?

Given the initial bearing of a lighthouse from the ship is N 37° E. So, $\angle ABN$ is 37°. We can see from the diagram that $\angle ABC$ would be $180-37=$ 143°.

Also, the new bearing is N 25°E. So, $\angle BCA$ would be 25°.

Now we can find $\angle BAC$ . As the sum of the internal angle of a triangle is 180°.

$\angle ABC+\angle BCA+\angle BAC=180\\143+25+\angle BAC=180\\\angle BAC=180-143-25\\\angle BAC=12$

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.

And let us assume the distance between the lighthouse and the ship at N 25°E is $AC=x$

We can apply the sine rule now.

$\frac{x}{sin(143)}=\frac{2.5}{sin(12)}\\ \\x=\frac{2.5}{sin(12)}\times sin(143)\\\\x=\frac{2.5}{0.207}\times 0.601\\ \\x=7.26\ miles$

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.

3 0

3 years ago