Answer:
20.52 grams of BrCl will be produced
Explanation:
Step 1: Data given
Mass of Br2 = 14.21 grams
Cl2 is in excess
Molar mass of Br2 = 159.81 g/mol
Molar mass BrCl = 115.36 g/mol
Step 2: The balanced equation
Br2(g) + Cl2(g) → 2BrCl(g)
Step 3: Calculate moles Br2
Moles Br2 = mass Br2 / molar Br2
Moles Br2 = 14.21 grams / 159.81 g/mol
Moles Br2 =0.08892 moles
Step 4: Calculate moles BrCl
For 1 mol Br2 we need 1 mol Cl2 to produce 2 moles BrCl
For 0.08892 moles Br2we'll have 2*0.08892 = 0.17784 moles BrCl
Step 5: Calculate mass BrCl
Mass BrCl = moles BrCl * Molar mass BrCl
Mass BrCl = 0.17784 moles * 115.36g/mol
Mass BrCl = 20.52 grams
20.52 grams of BrCl will be produced