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garik1379 [7]
1 year ago
13

Question 1 of 10What does the second quantum number (1) describe?O A. Which sublevel the electron is inB. Which energy level is

being occupiedOC. What spin a specific electron hasOD. The specific orbital within a sublevel
Chemistry
1 answer:
scoundrel [369]1 year ago
7 0

Explanation:

The second quantum number also called the orbital quantum number describes the type of orbital or shape of it.

Answer: D. The specific orbital within a sublevel.

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no

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How many molecules are in 4.08 moles of CCL4
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3 years ago
a beer's law plot was generated and the trendline had a slope of 137.2 l/mol. the absorbance of the unknown phosphate sample was
Lorico [155]

The phosphate concentration of the unknown sample is <u>0.002 M</u>

<u />

Beer's law, the quantity of power absorbed or transmitted by using a solution is proportional to the solution's molar absorptivity and the awareness of the solute. In easy terms, a greater focused answer absorbs greater light than a more dilute solution does.

C = εa/b

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   =<u> 0.002 M</u>

A sequence of fashionable solutions containing a purple dye was made by diluting an inventory answer and then measuring the percent transmittance of every answer at 505 nm (greenish blue). This wavelength became decided on with the aid of examining its absorption spectrum.

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7 0
1 year ago
The recommended dietary allowance for calcium for teenage children is 1,300 mg per day.
PtichkaEL [24]

Answer:

c) 35 fl oz

Explanation:

Hello,

In this case, to compute the recommended amount of calcium that the teenager must drink, one performs the following relationship:

8.0-fl \ oz -->298mg\\x-->1,300mg

Solving for x, one gets:

x=\frac{8.0-fl \ oz *1,300mg}{298mg} \\x=35-fl \ oz

Best regards.

5 0
3 years ago
After you preform your experiment, you determine that the kf value for naphthalene is 6.91 °c/m . you are using 10g of naphthal
Masteriza [31]
Answer is: molar mass of compound is 154,58 g/mol.<span>
m(</span>naphthalene<span>) = 10 g = 0,01 kg.
m(unknown compound) = 1,00 g.
</span>Δ<span>T (solution) = 4,47 °C.
Kf(</span>naphthalene) = 6,91°C/m<span>; cryoscopic constant.
M</span>(unknown compound) = Kf(naphthalene)· m(unknown compound) ÷ m(naphthalene)<span> · ΔT(solution).
M(xylene) = </span>6,91°C/m<span> · 1 g ÷ 0,01 kg · 4,47</span>°C<span>.
M(xylene) = 154,58 g/mol.</span>
8 0
3 years ago
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