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MaRussiya [10]
3 years ago
14

At what temperature will water boil under apressure of 787mm?The latent heat of vaporization is 536 k cal per gram.​

Physics
1 answer:
astra-53 [7]3 years ago
8 0

Answer:

.mmmmmmnmmmmmmnmmmmmmmmmm

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GETTING TIMED PLS HELP! Do the runners in the picture above represent kinetic or potential energy? you need to explain why.
prohojiy [21]

Answer:

<em>They represent kinetic energy</em>

Explanation:

<u>Kinetic Energy </u>

A body can do work due to some of its attributes or states. For example, its mass can do work if used to provide energy, if the object is at a certain height respect to some reference level, it can do work when going downwards (potential energy), if the object moves at a certain speed, it can do work when transferring part of its speed to other objects. It's called kinetic energy and is given by

\displaystyle K=\frac{mv^2}{2}

Both runners are moving in a horizontal path, thus they have kinetic energy, given by the above equation. If they could jump below ground level, then they will also have potential energy

8 0
2 years ago
What would happen if both the radius and mass of a planet were cut in half
Shtirlitz [24]

Explanation:

According to formula

g = GM/R^2

when mass is halved the value of g becomes half but when radius is halved the value of g increases 4 times.

As a result of both value of g becomes twice.

5 0
3 years ago
A simple series circuit consists of a 120 Ω resistor, a 21.0 V battery, a switch, and a 3.50 pF parallel-plate capacitor (initia
slega [8]

Answer

Integral EdA = Q/εo =C*Vc(t)/εo = 3.5e-12*21/εo = 4.74 V∙m <----- A)

Vc(t) = 21(1-e^-t/RC) because an uncharged capacitor is modeled as a short.

ic(t) = (21/120)e^-t/RC -----> ic(0) = 21/120 = 0.175A <----- B)

Q(0.5ns) = CVc(0.5ns) = 2e-12*21*(1-e^-t/RC) = 30.7pC

30.7pC/εo = 3.47 V∙m <----- C)

ic(0.5ns) = 29.7ma <----- D)

8 0
3 years ago
What is the weight of a 10-kilogram object on Earth?
Rasek [7]
98 N weight on object
8 0
3 years ago
Can someone help me?!!!!!
kramer

Answer:

Parabola

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform motion along the horizontal (x) direction, with constant velocity v_x. In fact, there are no forces acting along this direction (if we neglect air resistance), so the acceleration is zero and the velocity is constant

- An uniformly accelerated motion along the vertical (y) direction, with constant acceleration g=9.8 m/s^2 downward (acceleration due to gravity). This acceleration is due to the force of gravity that pulls the projectile downward.

The composition of these two motions gives a parabolic trajectory. In fact, the equations of the motion along the two directions are:

x(t) = v_x t (1)

y(t) = h + v_y t - \frac{1}{2}gt^2 (2)

Solving for t in eq.(1),

t=\frac{x}{v_x}

and substituting into (2)

y(t) = h + \frac{v_y}{v_x}x - \frac{1}{2}g(\frac{x}{v_x})^2

which is the equation of a parabola.

5 0
3 years ago
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