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ryzh [129]
3 years ago
6

The graph of the relationship between the volume of a gas at constant temperature and its pressure is a(n)?

Physics
1 answer:
timurjin [86]3 years ago
5 0
<span>When the difference between two results is larger than the estimates error, the result is</span>
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A protostar's radius decreases by a factor of 100 and its surface temperature increases by a factor of two before it becomes a m
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Answer:

L_f = K (\frac{r}{100})^2 * (2T)^4

L_f = K \frac{r^2}{10000} * 16 T^4

L_f = \frac{16}{10000} k r^2 T^4 = \frac{1}{625} k r^2 T^4

L_f = \frac{1}{625} L_i

So then we see that the final luminosity decrease by a factor of 625 so then the correct answer for this case would be:

B. Decreases by a factor of 625

Explanation:

For this case we can use the formula of luminosity in terms of the radius and the temperature given by:

L_i = K r^2 T^4

Where L_i = initial luminosity, r= radius and T = temperature.

We know that we decrease the radius by a factor of 100 and the temperature increases by a factor of 2 so then the new luminosity would be:

L_f = K (\frac{r}{100})^2 * (2T)^4

L_f = K \frac{r^2}{10000} * 16 T^4

L_f = \frac{16}{10000} k r^2 T^4 = \frac{1}{625} k r^2 T^4

L_f = \frac{1}{625} L_i

So then we see that the final luminosity decrease by a factor of 625 so then the correct answer for this case would be:

B. Decreases by a factor of 625

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