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umka2103 [35]
4 years ago
12

Nancy bought an extra-large bag of 1,288 beads to make necklaces. When she got home, she found another bag with 784 beads in it.

If she uses all of the beads and uses 56 beads per necklace, how many necklaces can she make?
Mathematics
2 answers:
TEA [102]4 years ago
6 0
She can make 37necklaces 
tekilochka [14]4 years ago
5 0

We are given

Nancy bought an extra-large bag of 1,288 beads to make necklaces

When she got home, she found another bag with 784 beads in it

so, total number of beads =1288+784

total number of beads =2072

now, we have

For one necklace , 56 beads are required

so, 56 beads = 1 necklace

1 bead=\frac{1}{56}necklace

for 2072 beads

2072*1 beads=2072*\frac{1}{56}necklace

2072 beads=37necklace

so,

number of necklaces she can make is 37..........Answer

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8 0
4 years ago
Please answer thanks! Brainliest
dimaraw [331]

Answer:

D - T-H is negative

Step-by-step explanation:

So lets go through what we know:

M is on the left side of 0, so M is negative.

A is also one the left side of 0, so A is negative.

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Lets go through each answer and see if it is accurate or not:

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With what we know, M is negative and H is postive.

Looking at the graph, we can see that M is farther to the left than H is to the right.

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Next we have the answer to A divided by H is negative

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This is not what our answer states, as it says it should be negative.

So next off, we have the product of H and A is postive.

Product means multipication.

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Since it is multipication, and we know a negative and postive make another negative, this would make it incorrect

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