Answer:
(a) -202 m/s²
(b) 198 m
Explanation:
Given data
- Initial speed (v₀): 283 m/s
- Final speed (vf): 0 (rest)
- Time (t): 1.40 s
(a) The acceleration (a) is the change in the speed over the time elapsed.
a = (vf - v₀)/t = (0 - 283 m/s)/ 1.40s = -202 m/s²
(b) We can find the distance traveled (d) using the following kinematic expression.
y = v₀ × t + 1/2 × a × t²
y = 283 m/s × 1.40 s + 1/2 × (-202 m/s²) × (1.40 s)²
y = 198 m