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Lena [83]
4 years ago
6

In the laser simulation when pumping photons into a two-state system, you could adjust the lifetime of how long an excited atom

stays excited before it releases its energy in the form of a photon. If you decrease the lifetime of the excited state, what happens?
Physics
1 answer:
Lunna [17]4 years ago
4 0

Answer:there won't be enough atoms that are excited around to undergo stimulated emmision

Explanation:

Stimulated Emission is the process used in laser operations to produce photons.

In stimulated emission a passer-by photon stimulates the atom to emit a photon, identical to the passer-by photon, immediately. The con to this is that the same passer-by photon could instead get absorbed by a de-excited atom.  Therefore, aside of atom excitation we need to use witty ways to insure that there are more excited atoms that could use the passer-by photon for stimulated emission than there are de-excited atoms.

Photons produced by this stimulation have the same wavelength which enables efficiency as all photons are emitted into the same node.

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An object is moving at a velocity of 23 m/s. It accelerates to a velocity of 85 m/s over a time of 8.3 s. What acceleration did
Bess [88]
\frac{v \: final \: - v \: initial }{time} = \: a
\\ \frac{85 - 23}{8.3} = 7.467 \: \frac{m}{ {s}^{2} }
7 0
3 years ago
Read 2 more answers
Which vector has an x-component with a length of 4?
zepelin [54]

Answer:

C.) vector C

Explanation:

From the graph provided:

Four vectors are present :

Vectors a, b, c and d.

The x-component of the vector is its magnitude along the x-axis.

Taking the coordinate of each vector:

Vector a = (1,4) : length of x- component = 1

Vector b = (1, 1) : length of x- component = 1

Vector c = (4, -4) : length of x- component = 4

Vector d = (-3, 4) : length of x- component = - 3

Therefore, vector c has an x-component length of 4

7 0
3 years ago
Can you help me with this?
Natasha2012 [34]

Answer:

no

Explanation:

so basically I am domb so I can not help you

4 0
3 years ago
Which celestial body would have the strongest gravitational pull on a satellite orbiting 100 km above its surface? Explain your
Andreyy89

Answer:

Jupiter

Explanation:

Since the mass of Jupiter is the greatest from the given choices, it will exert the most force on any object orbiting 100km above its surface.

This is compliance with the Newton's law of universal gravitation which states that "the force of attraction between two bodies is directly proportional to the magnitude of their masses and inversely proportional to the distances between them".

  • Therefore, the more the masses of two bodies, the higher the gravitational attraction
  • Since the distance is the same, the planet with the greater mass will exert the most force on the satellite.
3 0
3 years ago
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Male Rana catesbeiana bullfrogs are known for their loud mating call. The call is emitted not by the frog's mouth but by its ear
Sidana [21]

Answer:

The amplitude of the eardrum's oscillation is 6.65×10^-13 m.

Explanation:

Given data:

The sound has a frequency of 262 Hz

The sound level is 84 dB

The air density is 1.21 kg/m^3

The speed of sound is 346 m/s

Solution:

As, Intensity of sound is given by,

I = Io×10^(s/10 db)

I = 2×π^2×ρ×v×f^2×Sm^2

Thus,

Sm = √(Io×10^(s/10 db)) / √( 2×π^2×ρ×v×f^2)

Now, put the values,

Sm = √( 10^-12 × 10^(84/10) ) / √( 2×(3.14)^2×1.21×346×(262)^2 )

Sm = √(2.51×10^-4 / 5.66×10^8)

Sm = √0.443×10^-12

Sm = 6.65×10^-13 m.

8 0
3 years ago
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