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valina [46]
3 years ago
13

G = 10 N/kg or 10 m/s2

Physics
1 answer:
Irina18 [472]3 years ago
5 0

Answer:

a) U_{g} = 40\,J, b) \eta = 70\,\%, c) v = 20\,\frac{m}{s}

Explanation:

a) The initial potential energy is:

U_{g} = (0.2\,kg)\cdot \left(10\,\frac{m}{s^{2}} \right)\cdot (20\,m)

U_{g} = 40\,J

b) The efficiency of the bounce is:

\eta = \left(\frac{14\,m}{20\,m} \right)\times 100\,\%

\eta = 70\,\%

c) The final speed of Danielle right before reaching the bottom of the hill is determined from the Principle of Energy Conservation:

K = U_{g}

U_{g} = \frac{1}{2}\cdot m \cdot v^{2}

v = \sqrt{\frac{2\cdot U_{g}}{m} }

v = \sqrt{\frac{2\cdot (40\,J)}{0.2\,kg} }

v = 20\,\frac{m}{s}

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Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
Reika [66]

Answer:

v = 21 m / s

Explanation:

We can solve this exercise with the kinematics equations, let's start by finding the acceleration of the train with the initial data

            v = v₀ + a t

the initial speed is the speed within the city 6 m / s, the final speed is v = 11 m / s and the time is t = 8 s

             a = (v-v₀) / t

             a = (11 - 6) / 8

             a = 0.625 m / s²

when it leaves the city with speed vo = 11 m / s it accelerates for t = 16 s

            v = v₀ + a t

            v = 11 + 0.625 16

             v = 21 m / s

4 0
4 years ago
1. Summarize What are the four conditions of a<br>purely competitive market?​
bearhunter [10]

Answer:

Explanation:

1. Many buyers and sellers participate in the market.

2. Sellers offer identical products.

3. Buyers and sellers are well informed about products.

4. Sellers are able to enter and exit the market freely.

5 0
3 years ago
A shot putter shoots a 7.3kg shot from rest to 14m/s in 1.5s. what was the average power?
sweet [91]

Answer: 477W

Explanation:

Given the following :

Mass (m) = 7.3kg

Initial Velocity (u) = 0

Final velocity (v) = 14m/s

time (t) = 1.5s

Power = workdone (W) / time (t)

The workdone can be calculated as the change in kinetic energy (KE) :

Recall ;

KE = 0.5mv^2

Therefore, change in KE is given by:

0.5mv^2 - 0.5mu^2

Change in KE = 0.5(7.3)(14^2) - 0.5(7.3)(0^2)

Change in KE = 715.4J

Therefore ;

Average power = Workdone / time

Workdone = change in KE = 715.4N

Average power = 715.4 / 1.5

Average power = 476.93333 W

= 477W

5 0
4 years ago
A physics student of mass 51.0 kg is standing at the edge of the flat roof of a building, 12.0 m above the sidewalk. An unfriend
balandron [24]

Answer:

Explanation:

The wheel and falling student will have common acceleration .

For rotational motion of wheel

Tx r = I α , T is tension in the crank , α is angular acceleration of wheel  , I is moment of inertia , r is radius of the wheel.

= I a / r

T = I a / r²

For motion of student

Mg - T = Ma , M is mass of the wheel.

Mg - I a / r²  = Ma

Mg = Ma +I a / r²

Mg = (M +I  / r²)a

a = Mg / (M +I  / r²)

= 51 x 9.8 / ( 51 + 9.6 / .3² )

499.8 / (51+ 106.67 )

= 499.8 / 157.67

= 3.17 m / s².

If time t is taken to  fall by 12 m

12 = 1/2 a t²

24 / a = t²

24 / 3.17 =t²

t²= 7.57

t = 2.75 s

velocity to reach sidewalk

v = u + at

= 3.17  x 2.75

= 8.72 m / s

5 0
3 years ago
The cycle that is the slowest because there is no gas phase is the _____ cycle.
topjm [15]
It would be B. phosphorus
4 0
4 years ago
Read 2 more answers
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